Electrical Engineering: Ch 3: Circuit Analysis (36 of 37) Solving Basic Transistor Circuit (MESH) 1

In this video I will solve the basic transistor circuit using the MESH analysis method.

Next video in this series can be seen at:

[rayvasquez]

Mr Van Biezen thank you very much for your videos. I think there is a mistake in KVL3. Starting at the emitter and moving up to the collector there is a voltage rise so V0 is positive. The real collector current coming out of the 16v source is flowing counter clockwise so polarities across the 1000 ohm resistor is negative with respect to the collector node and positive with respect with the node connected to the 16v source. It has to be this way since the node between the 1000 ohm resistor is held at positive by the voltage source. This means that for current to flow through the 1000 ohm resistor the node connected to the collector has to be at a lower potential than the node connected tot the voltage source. This makes the voltage across the 1000 ohm resistor a voltage rise and then a voltage drop on the 16 voltage source.

[nararguerrero]

This problem is from fundamentals of electrical engineering. Thanks!

[aniketkale]

Thank you for the amazing explanation this made the problem look very easy.. Kudos to you.

[onurcandir]

Hello Mr Van Biezen I am a follower of you for years. Actually I am a medical doctor from Turkey and I am a physics and electronics hobbyist. Thank you very much for your lecture videos. I really appreciate your works. If it is appropriate for you, could you do some videos about semiconductors? They are really important in order to understand basics of electronics. Thank you. Sincerely

[robertcliffort]

Mr Van Biezen thank you very much for your videos.

[ARTUROCK]

Mr. Van Biezen: I really like that you have put all those problem solving electronics  online, it really gives me an idea. But those how you get those equations is great but it is really hard for me, I am trying to prepare for a job opportunity test and I have seen a few of your videos, thank you for that. Keep the good work!! hopefully there is a simple way for us not great at math and resolving equations.  I am ok with stablished formulas and ohms law, staff like that.  Thank you.

[nomunsheikh]

Sir please 🙏 make a video about that clockwise direction in KVL #3.

[adik]

Sir, what are the circuit configuration, where we may encounter 1st loop, can this be used for voltage divider bias

[pawepasierbek]

Mr Van Biezen, shouldn't it be Vo + 1000I3 - 16 = 0, in KVL3 (' +' instead of ' - ' in UR3)?

[ahcenedahmane]

We could use source transformation or Thevenin équivalent to simplify the left part then apply the same maths of video 35
Thanks anyways

[denizturk]

thank you for good quality educational content!

[trickytricks]

I don't understand the third mesh KVL analysis. Shouldn't the 1000I_3 term be positive? As the collector current is against the direction of our travel around the loop, giving a voltage rise (instead of voltage drop)

[bench]

i hope for more videos about semiconductor components.

[abhin]

Sir why there is no 0.7v drop in kvl 3 ? It must be there right ?

[Enigma]

If beta can vary so much across different transistors and we don't really want our circuit to heavily depend on a specific beta, are these calculations very accurate?

[kingrenny]

Great video but very confused why isnt there 0.7 when we find Vo but we use 0.7 In Loop 3 to find the current through the base.

[TUShamanking]

How do you do Mr.Michel van Biezen. i don't understand why 1000 ohm resistor in KVL3 is -1000. i think that in KVL is summation voltage input = summation voltage output . so  16V = V0 + 1000(I3)  then V0 +1000(I3) V=0

[MyKelsNotEveryonesKel]

Hi sir. at KVL 3 why Vo-1000i3-16V=0 ?. I looked at your previous video, the idea was Vo+1000i3-16V =0. Sorry for my bad english sir.

[Meneltour]

so... if the resistor in i3 was the v0 is negative? that means that the resistor limits the beta value right? doesnt that messup the i3 in the I3=150*Ibase because the amplification is lower? basically what i am asking is whould the resistor affects i3 if it was a high enough to limit the beta amplification?

[matas]

How do we solve this circuit if we assume Ie is not =150Ib but rather =151Ib ? do we have to redraw the cirtuit as shown in the next video to solve it in this way?
I assume this way, as shown in this video, in KVL we are ignoring I2 when writing the quation which is the missing Ib?