Electrical Engineering: Ch 3: Circuit Analysis (25 of 37) Mesh Current by Inspection: Ex. 4

In this video I will set up the equations to find the 5 currents of a circuit with 4 voltage sources using mesh analysis by inspection.

Next video in this series can be seen at:

[davidkatandi]

Dr. Your videos have been of a great help to me. Thank you very much and please continue to upload as many as can. May the Lord bless you.

[ShaunStruwig]

for anyone wondering: i1 = -0.72A, i2= - 1.99A, i3=-0.49A, i4=0.21A, i5=0.38A. Answer courtesy of Matlab :D

[leoclarkin]

Dear Michel, marvellous clear and concise methods of working through the problems. I'm a graduate EE, but 38 years ago. An excellent refresher, but not sure if I really understood whilst in college! Thx

[wexosldaniechan]

wow they are so easy to understand the way u explain

[edutechcinemavr]

If at voltage source there is current source present
Then how we apply trick

[tkhagos]

On another note though, who would dislike this video!?

[mohammedyalferjany]

thanks Dr . your videos are very helpful

[noraniad.disimban]

Indeed! It’s a complicated problem. Luckily I still get the right answer!yey! (I now read other comments hihi 😊 )

[felixjaja]

How can I see other videos on Maxwell's matrix method

[mareklewanski]

What I dont know is that I am not sure where to place I2 - is it after voltage source of 6V before the node or somewhere else like resisor 3 ohms or 1ohm...? Please help me.

[kenshinchia]

Hi professor, how about if there is a current source in one loop?

[mr.feeler]

Thank you so much for this videos Sir. This helps me a lot better than in our school. ☺️😍

Please make some examples of supernode and supermesh ☺️ Thanks

[sudhanshutrivedi]

how can we solve if there will be any current source in the circuit...

[aminerkin]

i1 = -1238/1431, i2 = -3172/1431, i3 = -2060/1431, i4 = -388 / 1431, i5 = 92/ 1431