Electrical Engineering: Ch 3: Circuit Analysis (3 of 37) Nodal Analysis w/ Current Sources: Ex. 1

In this video I will find the currents of a circuits with 2 current sources using nodal analysis.

Next video in this series can be seen at:

[Thefarnworth]

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[qqwwqq]

lol even his revision in the end taught me a lot more than the tiring 1-2 hour lectures of other teachers

[duanebarry]

Thank you. I find your lectures easier to follow than those from my classes in college.

[santiagofossi]

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[yzhang]

Thank you for posting these videos for free.

[Rethyms]

Was able to solve this without looking a single time at the video thanks to your great explanation in the previous video, thank you!

[nararguerrero]

This example is from fundamentals of electrical engineering. Thanks! Support this guy!!!

[maheshwarsambari]

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[nilanjanchatterjee]

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[renadalghamdi]

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[belloayodeji]

I got whole numbers
i1=4A
i2=-2A
i3=6A
and I have cross check using the kcl

(I1)The 1st current source is 6A
(I2) The 2nd current source is 2A

i1=I1+i2
4A=6A+(-2A)

i3=I1+i2+I2
6A=6A+(-2A)+2A

[mositothabane]

AM STRUGGLING ALOT BUT U TRIED TO MAKE THIS CCT LOOK VERY SIMPLER

[AN]

This is so amazingly good explained. Thank you very much!!!

[Thefarnworth]

Sorry, but confused; 5 times -3 = minus 15.
Minus 3 times 1 = 3. I know I must be missing something, could you please explain. With thanks and I really appreciate your work.

[mohitparashar]

Thank you so much sir for these lectures

[varkolynkolta]

We have in the class learnt that choosing the node connecting the most branches is best practice (I think the node we marked V1 in this example.); also, we note every possible current exiting the nodes; is it okay?

[problemdog]

Sir can you explain how to cross check the answer from the circuit I didn't get that though

[maryamabdelkawy]

thank you soo much you helped me alot .... really .. :D

[sihaskumarasingha]

Sir, I understand that if we assume a wrong direction for the current, it's ok because we'll just get a negative answer. However, if we assume the voltages wrong (for example if i took i2 as (V2-V1)/4, I do not get a proper value for V1 and V2.
Would very much appreciate a reply.
Thank you in advance!!

[TheStrafendestroy]

Why not set up the linear equation before the substitution you should get the same answer correct? Then you can just sub in the smaller current definitons