Electrical Engineering: Ch 3: Circuit Analysis (8 of 37) Nodal Analysis w/ Voltage Sources: Ex. 1

In this video I will find the currents of a circuits with 2 current and 1 voltage source using nodal analysis.

Next video in this series can be seen at:

[daayemshehzad]

I cannot even explain the love I feel for this man. God bless his soul for all the circuitry he has helped us with. Amen.

[jcastaneda]

Not a question at all but Sir I want to seriously thank you for all of the time and effort you put into your vids, Last semestre I stumbled upon your channel just to find that there was a treasure to be found. I'm currently studying an Electrical Engineering degree in Chiapas, México. I want you to know how greatful I really am for what you do here. Whenever I can, I always share your content with my classmates and even though a language barrier exists, that doesn't stop us from learning the same method in another fashion. Knowledge is universal, thank you for showing me that. Saludos desde Chiapas profesor. Much love.

[butchmcbride]

Thank you for sharing your awesome knowledge with us. I wish this was available when I tried attending engineering school in my mid-forties. I was not able to finish, and now I am 65 years old still with a desire to learn. Thank yoiu

[vicallday]

You, sir, single handedly summarized the past moth of my ECE 2k level course. Thank you.

[brewertonpaul]

I have exam on June 4th, University is closed due to coronavirus and I was panicking. Thanks for your hard work putting these videos together as you are going to help me out. Reading books is okay, but sometimes you need someone to talk you through it, that is exactly what you are doing now. Much appreciated.

[Zeyad-zahran]

والله يجدو انت عسل وشرحك جامدi appreciate what you do your student from Egypt

[antonionunez]

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[WilliamDyal]

Sir like honestly God bless you, that's all I can say.

[c]

I really appreciate your videos. The are so concise and to the point but also very explanatory. You're an Electrical engineer but have a very mechanical way of doing things. I really dig the bow tie

[kwasibempong]

Thanks you are awesome. Currently in Ghana doing basic electronics and I'm really grateful. Crisp and clear explanations Keep it up..

[guntergerdjuliovaderramaso]

Amazing how you used the Super Node!!!Thanks a lot for that super explanation!!!But there is only one mistake in current i1, it is: i1 = 5, 6667 A (is wrong 0, 2 A), i2 = -3, 6667 A (it's ok) and i3 = -1, 3333 A (it's ok too), so i1 + 12 = 2... 5, 6667 + -3, 6667 = 2 in node v1... in node v2 we get: i1 = i3 + 7, replacing the values: 5, 6667 = -1, 3333 + 7, that is 5, 6667 + 1, 3333 = 7 (ok). Finally we have in ground node, where V = 0: i2 + i3 + 7 A = 2 A, replacing the values: -3, 6667 + -1, 3333 + 7 = 2, that is -5 + 7 = 2 (ok). I hope it helps a little for clarifying this problem!!!

[krystygaytan]

This example is also an example in the book im using for my online class. Your video was a great help since the book lacks the detail you provide. I am forever grateful.

[NoCaminhoDele]

In a later video, you used nodal analysis to solve a circuit with a voltage source without using a super node. It made me wonder why the super node was necessary here, so I came back and found that this circuit can also be solved without a super node. (It did however involve assigning a current between v1 and v2, but that turned out to be easy enough.) I also want to say thanks for these videos. They're extremely helpful!

[briandindi]

You're the best I couldn't understand from my lecturer PDF. God bless you sir

[jahidem]

Thank you Sir for making all these videos. You are a great teacher.
I'm really enjoying your videos.

[alyzadeguzman]

you should be the one receiving my professor's salary. you are a lifesaver <333

[romelelectronics]

at 6:40 he did so good kidding see 2 camera :D I love u sir :)

[greatasam]

Sir, how did we get v2 to equal (v1 + 2) if we assumed that current i1 is flowing from node 1 to node 2? Thanks!

[kallewulf]

Thinking about this i believe it would make sense to assign one of the nodes connected to the voltage source as the reference node (with 0V). This immediately would give us the voltage of the other node connected to the voltage source (in this case 2V). It is basically the same logic, but the numbers & calculations would be a little bit easier.

[maheemalhafiz]

Can we transform the sources to solve this using KVL? For example, can the current sources be transformed to voltage sources?
I would also like to add the fact that there's no words I can use to express my gratitude towards you professor, these videos are the only reason I'm surviving my course. Thank you so much!