Solve a First-Order Homogeneous Differential Equation - Part 1

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This video explains how to solve a first order homogeneous differential equation in standard form.
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I honestly spent all of last night and today watching your playlists; Exact o.d.e, homogeneous o.d.e, Bernoulli o.d.e, Integrating Factor o.d.e, and Separable o.d.e and took tons of notes! I am so ready for tomorrow's midterm! You're the best.

cristianmorales
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Watching ur 8 minutes video is more beneficial than spending 75 minutes in my class

blackroze
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Thank you so much it's very helpful, I have no idea why my professor wouldn't just use the V when substituting instead he use AT+B and It got me so confused

ameer
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dude!
 I've been stuck on this for a couple of days mainly cuz of the dv/dx substitution bit, thanks to you I finaly get it! you're awesome!

ahmedislam
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I like this way better Just dipping into this while using the formulas and staying the path works.. :D

Charlietheleet
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Thank you so much. I learned what I was struggling about

tabassommadayen
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thank you so much sir this was very helpfull to me....

nivedhasuriyamoorthy
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which is the method to solve homogeneous differential by substitution like y=vx or by integrating factors or that we can solve by both methods?

ahmedarshad
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hi, it is a great video honest I think you deserve a big thank you, but do you mind explaining what happened to the when you multiplied by x^-2 in the numerator I believe it should have been v/x? politely asking,

mandla-nkosi
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Thank you so much, this made my concept very clear

darshanmajmudar
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3:11 where did dy/dx=x(dv/dx)+v come from?

Tieshoes
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How did u divide the numerator with v^-2?

PureBasicstuff
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Is this just nothing but algebra? All I see is just using algebra throughout to get the general solution. (I was told I would be using calc 2 mostly to help me do Diff EQ). But this just looks like we are doing algebra techniques

JHnat
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this doesnt seem all that different from my algebra homework, just with knowing more concepts and rules to apply when manipulating algebraically

gregsancientegyptfactsandg
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on the last part, why did u reciprocate both sides of the equation? thanks

zsylechano
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why is it v^-2


shouldn't it be +2

kek
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Hmmm. Isn't (y^2/x^2) different from (y/x)^2??? Because if you put a value on the variables it is so different, they have different answers.

patricklabra
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