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SAT Math Prep: Algebra Problem 5 | Linear Equations

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Linear Equations - High School Math Question for Grade 8 (Pre-Algebra and Algebra 1).
Given the equation below, solve for x:
−3(2x+4) + 5 = 2(x−7) − 1
Distribute the terms:
-3(2x) + -3(4) + 5 = 2x + 2(-7) - 1
This simplifies to:
-6x + (-12) + 5 = 2x + (-14) - 1
Then:
-6x - 12 + 5 = 2x - 14 - 1
Resolve the additions and subtractions on both sides:
-6x - 7 = 2x - 15
Subtract 2x from both sides:
-6x - 2x - 7 = 2x - 2x - 15
This simplifies to:
-8x - 7 = -15
Add 7 to both sides:
-8x - 7 + 7 = -15 + 7
This simplifies to:
-8x = -8
Divide both sides by -8:
-8x / -8 = -8 / -8
Final answer:
x = 1
#sat
#satmath
#satmathprep
#algebra
#algebra1
#shorts
Given the equation below, solve for x:
−3(2x+4) + 5 = 2(x−7) − 1
Distribute the terms:
-3(2x) + -3(4) + 5 = 2x + 2(-7) - 1
This simplifies to:
-6x + (-12) + 5 = 2x + (-14) - 1
Then:
-6x - 12 + 5 = 2x - 14 - 1
Resolve the additions and subtractions on both sides:
-6x - 7 = 2x - 15
Subtract 2x from both sides:
-6x - 2x - 7 = 2x - 2x - 15
This simplifies to:
-8x - 7 = -15
Add 7 to both sides:
-8x - 7 + 7 = -15 + 7
This simplifies to:
-8x = -8
Divide both sides by -8:
-8x / -8 = -8 / -8
Final answer:
x = 1
#sat
#satmath
#satmathprep
#algebra
#algebra1
#shorts