A Very Nice Exponential Equation | Can you solve?

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If you need to post a picture of your solution or idea:
2^{3^{4^x}} = 4^{3^{2^x}}
#ChallengingMathProblems #ExponentialEquations #Exponentials #Logarithms
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SIMILAR PROBLEMS 🤩

PLAYLISTS 🎵 :

[robertlunderwood]

A cleaner solution can be found if you do log base 3 and log base 2. x = log_2[1+sqrt(log_3(48))] - 1

[joeaberman]

if you plugging 1 and 0 instead of x you get a valid equation on both sides 4096^0 and 4096^1 will suffice

[zawatsky]

Почему вы никогда не превращаете напрямую, по определению логарифма? Если a^b=c, b=log(a;c). Зачем лишние манипуляции?

[Ghaith]

these videos are getting funnier .awesome

[DeJay]

On the surface it looks like a^x = b^x for a and b not equal so solutions seem impossible.

[wayneyadams]

The reason German's use k instead of c for constant is that at one time Britain was the greatest naval power in existence and they controlled all the seas.

[alimy.]

Hey there, what application do you use to write in the video?

[MrLidless]

In both sides immediately. *Much* shorter route and a 2 min video.

[zawatsky]

@Boulder Rush точно так же бесит это написание логарифмов на англосаксонский манер. У любого логарифма, начинающегося с "log", нужно указывать основание. Log₂3, например. То, что они называют log3, правильно записывается как lg3 (log₁₀3).

[raminrasouli]

I thought the solution set would be all complex numbers. It is true for all numbers.

[eckhardfriauf]

You claim acoustically that this is a nice exponential equation (0:02).
I like to contradict and refer to your written statement which reads "A Very Nice Exponential Equation". 🤪

[victorchoripapa]

Trying to figure out this, I've got X~0.524644
Am I right?