Finding a tangent plane.

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Very nice. You just need to fix the coordinates of the Point ( 1, 1, -2) values when calculating the Normal Vector Gradient F.
< 2x--2, -2y, -2z >|( 1, 1, -2) = < 0, -2, 4 >
Actually, you arrived at the correct Equation for a || Plane: y - 2z = 5. [Just that you mistakenly wrote ( 1, 1, 2)]. ♾️

neilmorrone
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Original equation was maybe z=... rather than z^2=... ? Otherwise the point (1, 1, -2) is not on the surface.

koenth