Computing a tangent plane

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Here you can see how to use the control over functions whose graphs are planes, as introduced in the last video, to find the tangent plane to a function graph.
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This is such a great video. After watching this I was able to solve all my equations right away with more understanding. Keep up the great work man, the visual representations played such a key role.

haroldh
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i wondered why you were talking so fast then i realised i had it on double speed :/

savagepinksock
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ye, lets call variable a y_not, y not.

MrGarkin
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This video saved me so much time, thank you!!!

TheAmunik
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thank you great video, finals tomorrow... one of the last things I had to figure out.

tylergeorge
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Thank you so much Grant, much appreciated

SW
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Thank you so much! Without you I would hate math!

arsalansyed
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Can you find dz/dx and dz/dy and then use the cross product to find the equation of the plane?

Otto-czby
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What happens if the chosen point x does not belong to the surface? How do you find the tangent surface in that case and how does that look in comparison with the one in the video?

angelgarciamath
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When you are so into maths it ends up consuming all of the remaining neurons you had 8:32

gnikola
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Why wouldnt the tangent planes equation be 0=a(x-x0)+b(y-y0)+c(z-z0) where a, b, c are the partial derivative of the surface evaluated at x0, y0, z0 ???

WorldWideSkboarding
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It seems like this only works with convex functions. Is that correct?

evanparshall
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Why f(x, y) and not f(x, z) or f(y, z)?

RafaelFix