Russia| Moscow Math Olympiad Question from 1995 | Second Method Geendle

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Hi, I have a question.
I am not completely sure but in the sqr( x^2 - 12/x^2), you muultiply the x^2 by x^2/x^2 to get x^4 before you simplify both the fractions to simply the sqr(^4 - 12 / x^2) by converting the x^2 to just x right? Sorry about that :p
Great vid btw 🙏

Stardust_sniper
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Sqrt(x^2)=IxI=+-x so (a+-b)^2=0 so....x^4-x^2-12=0 so x^2=4 so x=+2 or -2 Accepted And Second Case x^4+x^2-12=0 so x^2=3 and x=+sqrt3 or -sqrt3 Both Rejected because substituting x^2=3 to the Original the second Radical Is sqrt(-1) with impossible in R.

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