Math Equations But They Get Increasingly Harder

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[isavenewspapers]

Ah yes, x = 1. Truly a puzzler for the ages.

[davie]

4:32 Note: Thi s v i sual i zat i on i s a qual i t at i v e i l l ustrat i on, not an exact numerical sol ut ion of t heheat eq u at i on .

[bridgeon]

Math Olympiads seem to love functional equations

[empmachine]

You should make a video on the Residue Theorem, I bet it would rock!

[YouTube_username_not_found]

I miss the old days where you were solving insanely hard integrals.

I have already a suggestion. Do the integral that Cleo solved without showing her work and the answer was acrccos(sqrt(Phi)).

[kirahen]

Me getting to parabolas: ha! I know that one!

*See that I'm still 1 minute into a 5 minute video*
Mfw

[mathevengers]

I know all of them, no wonder I can't find a girlfriend lol

[Radii_]

Hello h
This guy makes beautiful mathematical videos

[LeTtRrZ]

Ah this video gives some insight into what Cauchy-complete means. I had seen that term used in quantum mechanics but didn’t know exactly what it meant.

[gracefulgrizzly]

Since when is there a quartic formula?

[wqltr]

1:23 im not sure that is an accurate description, sounds like you are describing quadratics to be honest

[imbadlydone]

At 5:16, how does he get f(1+1) = f(1) + f(1)? Also I don't think proving f(2) = 2f(1) means that f(x) = 2f(x) for all x?

[kevskevs]

Metamath question: Does anybody know why a general linear equation is written as "y=mx+b" in English? In German, it is usually written as "y=kx+d" (k for a "k"onstant slope, d for a distance along the y-axis). Why m and b?

[peterslattery]

Does anyone have any resources on functional equations? I’d want to learn more about them

[duckyoutube]

Ahhh yes partial derivatives.

The math where one problem can take hours to solve.

If you are familiar with binomial expansion just imagine that, but with limits, and with multiple variables.

Just to give you a hint lets find the derivative of just x^2....one variable raised to the second power.

Lim h->0 (f(x+h)^2 -f(x)^2)/h
Rewrite (expand)
Lim h->0 (f(x+h)(x+h) - x^2)/h
Rewrite (foil)
Lim h->0 (x^2+2xh+h^2-x^2)h
Rewrite (combine like terms)
Lim h->0 (2xh+h^2)/h


Last step(cancel out h, then sub 0 for h)


d/dx=2x

That took about 10 minutes just to write out. And that is a baby calc 1 problem.

[thejklbro.]

Bro none of this **** makes any sense.