Quadratic Equations IIT Questions No 11 ( X Class)

A quadratic equation is an equation in the form of ax^2 + bx + c = 0, where x is the variable and a, b, and c are constants. Quadratic equations can be solved using various methods such as factoring, completing the square, or using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a. The solutions to a quadratic equation are known as the roots and are represented by x1 and x2.

[tegniesjafar]

JEE Advanced 2023 IIT dholakpur Ka Question hai

[aim-iitdelhi]

JEE ADVANCED does not ask such easy questions, jee aspirants can feel it ❤❤ .

[PoonamYadav-rb]

Solved it without touching the pen while eating maggi...

Now I can crack IIT 🌚🌚

[nishant]

2 minutes silence for those who just entered class 11th, paused this vdo and solved this q and is happy to get the ans thinking this is iit level questions 😂

[_dekh-_-]

This question is from JEE-14(Jha*nt entrance examination 14)
Questions were prepared by honorable Professor Matsuzaka from IIT Kasukabe

[famous]

Useless for above 10 class 😂😂😂😂 saaaalae benstokes

[BhavishyaDhyani]

IITians be like Abe jee ke naam par ye to kuch bhi puch rahe hai😂

[solitary]

(α+β)^3=α^3+β^3+3αβ(α+β)
Now find the product αβ using this.
1=7+3αβ
You get αβ=-2

Hint: In the equation x^2-bx+c=0, b is sum of roots and c is the product of the roots.

[Doreamonnobix]

Cengage nhi kr paya to kya hua..Is que ko kar liya finally ab iit bombay mai 🕊 science mil jayega

[vijaybansal]

LEGEND give no smile at her correction ❤❤❤❤❤❤

[NomadicSoul]

By hit and trial we know that (-1) + 2 = 1
And (-1)³ + 2³ = 7
Hence alpha = -1 and beta = 2
So, x²-x -2 = 0

[hitsun]

Brilliant!!! formula was incorrect than also his answer was correct 💯💪💪💪😂😂

a³+b³ =(a+b)(a²- ab + b²) ✓

(a+b)³= a³+b³+3ab(a+b) ×

[technowallah]

IIT questions lol 😂. Which year's question is this? Can you tell us!!?

[xqfgod]

This videos production level predated the YouTube platform itself

[abhayazad_]

Thank you feature of your teacher good job
Sabash kya bat hai
10 second me answer

[ankitdutta]

If this is an IIT question then i am Newton 😅😅

[bharatmatakayoda]

Ok i don't know any of this alpha ir beta thing
However the way i tried to solve with trail method
First i assumed a= 2 and b = -1
(2)Cube + (-1) cube = 7
2-1 = 1
So
x×x- x-2
4-2-2 = 0
Am i right ?

[BesnikDule-flyb]

I think vieta's jumping formula will be better were in the equation ax²+bx+c
-b/c=x1+x2 now we know that x1=a and x2=b so x1+x2=1 so -b=c that will be a

[theerthaprasad]

If this type of que appears In jee advanced 2024 I will be air 1

[rishipramanick]

First u have to do cube in both sides then need to put values and alpha times beta will be -2 and product of roots is c by a so x2-x-2 = 0 is the correct answer
Otherwise u can put the values of alpha beta in every equation to see where it stands zero