Area under and between Curves by Integration | ExamSolutions

preview_player
Показать описание
SIGN UP FOR NOW FOR A 30-DAY FREE TRIAL

PREDICTIVE GRADES PLATFORM IS HERE 🚀

☑️ FREE ExamSolutions AI personal tutor
☑️ Accurate grade predictions
☑️ Personalised resources and tuition
☑️ Guaranteed results or get your money back

When finding an area under a curve to the x-axis we use definite integration. Several types of questions considered. Check out the contents below.

PAGE 1: Area under a curve above the x-axis 0:00:04

PAGE 2:
Example 1 0:01:31
Question 1 - Have a go 0:03:02

PAGE 3: Area below the x-axis 0:06::01
Don't make this common mistake 0:09:13

PAGE 4: Area above and below the x-axis 0:10:55

PAGE 5: Area between a curve and a line 0:14:27
Method 0:15:26
Worked solution 0:17:43

Page 6: Area between two curves 0:21:45

---------------------------------
Videos in this series:
INTEGRATION 1: What is Integration?
A look at basic indefinite integration
INTEGRATION 2: Definite Integration
Looks at definite integration and applications.
INTEGRATION 3: Area under a curve
Looks at areas under a curve to the x-axis, below the x-axis, between a curve and a line and between two curves.
INTEGRATION 4: Integrals of the form (ax+b)^n
--------------------------------------------------------------------------------------

Рекомендации по теме
Комментарии
Автор

To be honest mostly I don’t even comment on your videos even though I watched them in a regular basis, because I can’t describe you fully or thank you enough . your explanations are absolutely clear and understandable, also I love the way you organised your works . Thank you so much 😊

DaawaaMuslimaHunddaaf
Автор

Hi :)
I just wanted to say that your video really helped me! I have an integration test tomorrow and I didn't understand this part of the topic at all, but your video has made me understand what to do and I am very grateful.

Thank you!!

aditiaryal
Автор

3 years later and this video is still helpful amazing easy to understand explanation thank you sir

GIFT_AG
Автор

just in time for my mocks tomorrow <3 thank you

soushi
Автор

Wonderfully done. Hope you could make videos on physics and chemistry as well.

asogvideos
Автор

I am trying to prepare for the MAT test ahead of school AS level syllabus so your videos are a lifesaver particularly for the topics which I am unable to understand

varunnayak
Автор

Thanks a lot sir. Your explanations are simple but highly effective.

Mr_Blaacck
Автор

Love from Bangladesh. Thanks for pointing out common mistakes..

mohammedamanullah
Автор

Such brilliance!!! I am Surely going to achieve my goals with such explanation🎉🎉

beatricemulimba
Автор

What a life saver, thank you so much this was helpful

PatchyPaulina-jb
Автор

Thank you so much, this will save me on an exam some day

assaku
Автор

good explaination and really helpful, i can prepare for my examination

intannajla
Автор

Thank you very much. This video covered all of the subject matter in igcse edexcel further maths area by integration part. I'm still 15, and if I can figure it out, you all will figure it out. I highly recommend spending this 30 minutes watching this video. 🙏🙌

nethunamaraweera
Автор

Super explanation sir 👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👍👌

venkataramsai
Автор

This video help me to calculate area under the graph

amirandd
Автор

Thanks a lot, this was really helpful.

christophermoltisanti
Автор

Ummm excellent, you are a pure mathematician ..

tinodaisheganyani
Автор

Question - where there is a curve and a line intersecting, or two curves, then assuming both are "well behaved" across the domain we are looking at (in this case the upper and lower limits of the definite integral) - do we need to integrate once for each function, compute each area, and then subtract areas? Can we not subtract one function from the other and then integrate once?

In other words, forgive the notation, but is INT(f1(x))dx - INT(f2(x))dx not INT (f1(x) - f2(x))dx?

Can we not basically "pull" the integral out?

tanelkagan
Автор

got an exam in two hours and this helped a lot thank youu

nadeemjabla
Автор

25:21 sir shouldn't it be [-8/3 + 2 + 12] - [-9/8 + 9/8 - 9]
which gives 61/3 as a answer and the shaded area will be 397/24.
pls do correct me if I am wrong

arafabdullah