Calculus 2 - Integration: Finding the Area Between Curves (3 of 22) Ex. 3: y=sinx, y=cosx BEWARE!

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In this video I will find the area bounded by the 2 functions y=sinx and y=cosx and the lines x=0 and x=pi/2. Beware of how to set up the upper limits and lower limits of the integration.

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The red bow tie makes calculus so much more bearable

puppygirl

Really well made video. Very clear and helped a ton. Thanks.

MrCristie

A lifesaver, thank you so much for all your time and effort into creating these resources!

levihorudko

Thank you, these certain examples with flipped orders are rare in YouTube for some reason.

eaejbv

Helped me with my presentation in school. Although I had to do it in German because... obvious reasons. But excellent video.

Kenji-ugbo

Timestamp 4:27 How do we know that the halfway point (pi/4) coincides with the intersection of the two functions? Any reference videos please? Again, great video as always!

joeyborja

Since the the graph between 0-π/4 and π/4-π/2 are mirror image so can't we just 2x integration of [sin x] with limit being 0-π/4 ? would that be correct ?

lolololol

find the area to sin x and x axis between bay /2 to x = 2 pay

hazimalkurishy

Thank you, you just earned another subscriber!

fontanot

Is there any way to find the area by integrating as a single integral? Is there a way to keep the limits of integration from 0 to pi/2 ?

IvanMTG

bruh since when do y=sinx and y=cosx intersect and the x axis

aluminiumiodide

If Y2=SinX and Y1=Cosx Graph of SinX is not Correct.

irajnaghash

Sir i cannot catch up anything😭 i have similar question like this but its 0<x<2pi so its x = 0, x = 2pi isnt it?😭

dayangkhadraa

(x^2)d^2y/dx^2 –dy/dx –4x^3y =8x^3 sinx^2, x>0
Please help

sulphurnewsnetwork

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