Solving Exponential and Logarithmic Equations

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Now that we know how to use logarithms, we are ready to solve a whole new class of equations that we couldn't before! Whether these are logarithmic equations or exponential equations, using logs will allow us to get the answers we need.

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Whoops, at 5:51 I display two solutions for an equation, one positive and one negative, but the negative solution actually does not work because you can't take the log of a negative number! So only the positive solution works there, sorry for any confusion caused.

ProfessorDaveExplains
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profesor dave's intro is what gives me hope.

alexandralugo
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POV: you just wanna learn logarithmics, and you met jesus christ instead.

Gttyrrium
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I literally stopped going to my coaching institute and I feel I learn more from you, thanks professor dave!

lotharlaishram
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"And if we stare at this for a few seconds, we can see..." 5:41 😂🤣🤣, awesome technique: stare at equations. This is the best part of the video.
Your videos are awesome Professor Dave!

NiazAlly
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Thank you so much for ur vids i didn't take maths in my 11th grade so learning these concepts will help me alot to understand some parts in physics and chemistry 😀❤️

yukimaru
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At 5:50 x cannot be -1 since log2 (-1) is undefined for negative values of x.

karlzhu
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All was good until I had to solve them yikes

haniellopez
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Great explanation and engaging graphics! Good job, Professor Dave!

iZAPMath
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Bro you are insanely clever teacher thanks for every thing (I like the way you teach)

YabetseYoseph-meiw
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This video was very fun to follow along with, got to practice some log

RadoHudran
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what is the definition of a logarithm that makes 2 square or 4 = x square - 3x, how did you get the 4

citrecworldwide
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I'm kinda desperate now because my quiz in this subject will be tomorrow and Professor Dave explained it in detail.
Thanks, Jesus

fredvincentcaipang
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explanation as lucid as clear running water

basilrex
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Hi professor,
Can I also use the common log in the place of the natural log in problem number 4??

padmarajubapala
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can someone explain to me if a question: logx 4³ - logx 2 = 5?

syameerafif
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in the last question of the comprehension, it can be (-e -1) as well

bao
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For the comprehension problems, how did you get from log(3x-2)=1 to 10=(3x-2)? Did you apply log base 10 to both sides of the equation?

bushrao
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i understood his explanation and such but i couldnt answer the reading comprehension oh my gosh my calculus exam is tom. and its now 12 am midnigbt

paenk
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Last solution in comprehension section was pretty sipid. I only enjoy math when I understand it.

OkSid