Solving logarithmic equations by factoring

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👉 Learn about solving logarithmic equations. Logarithmic equations are equations involving logarithms. To solve a logarithmic equation, we first use our knowledge of logarithm laws/properties to express the terms in both sides of the equality sign as single terms. Then, we equate the numbers/expressions in the logarithms and hence solve for the unknown variable. Note that the logarithms must be of the same base.

If one side of the logarithmic equation have logarithm and the other side does not have logarithm, the equation can be easily evaluated by taking the terms in both sides of the equality sign as exponents of powers with the base of the power corresponding to the base of the term having logarithm. The base of the power cancels out the logarithm and then we can evaluate the unknown variable.

Organized Videos:
✅Solve Logarithmic Equations
✅Solve Natural Logarithmic Equations
✅Solve Logarithmic Equations
✅Solve Logarithmic Equations | Learn About
✅Solve Logarithmic Equations with Multiple Logs
✅Solve Logarithmic Equations with Logs on Both Sides

Connect with me:

#Logarithms #logarithmicfunctions #brianmclogan
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thank you for being straightforward, long lectures on math just always goes in one ear and out the other so things like this help a lot

isabelcamacho-perez
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By the definition of logarithm, it is directly 2^2 = x^2/(x+3); then this becomes quadratics equation. It ends up with x = 6 and x =-2; You are a great teacher. I wish I had the teacher like you in my high school, explaining everything clearly. Cheers!

BoZhaoengineering
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Very Good, Brian McLogan, Keep It Up! 🎉🎉🎉🎉

Sultan_A
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great explanation but for some reason im having some trouble with a similar equation where you add the 2 in front of the log aside from this one that multiplies. i have checked everywhere and cant find a clear source. thank you though

jaredguerra
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youve helped me through my 10-week online college math course. thank you 😭🙏 im rewatching these before the final tomorrow

milkbread
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Goodmorning sir, could you please make a video about on how to solve logarithmic inequalities? Thank you

josearielk.repollo
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Can someone help? Why did you reject the solution x=-2? I know logs can’t take negative inputs, however that 2 out front of the original equation means we would take x^2, therefore the input would always be positive. That’s why I thought it would still be a solution.

crod
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you are the BEST! thank you so much for your videos!!

amandanewell
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You are amazing.
Hope you were my teacher.

mr.knight
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I’m doing a question where log2(x+5/x)=3 how would I get my answer from that

saiemullah
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Shouldn't both be correct? logBase2 of x^2 where x=-2 is logBase2 of 4, minus logBase2(x+3) (which works out to be zero) is equal to 2. For 6, 2logBase2(6)-logBase2(9) will equal two as well.

lilaroseg
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what did you do with the two in log x. Where did it go?

michaelnguyen
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Thank you for your tutorial in log but it is not visible at all

papahapinesspatrick
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Dude -2 in the equation is going to be squared and become positive

mohammedkhaled
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why don't you ever do the problems I have on my actual homework? I have a equal sign in the middle, separating two logs.

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