Find the area of the unshaded region shown in the given figure | Q 25 Or Maths Standard

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Maths Standard Sample Paper 2023-24 Solution Class 10 CBSE | Class 10 Maths Sample Paper 2023-24 solution

Section - B
Question 25 Or : Find the area of the unshaded region shown in the given figure.

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R = 2. Area of one semicircle = (PI x R^2) / 2 = 6..283. There are 4 semicircles. 4 x 6.283 = 25.133. The square is 4 x 4 = 16.
25.133 + 16 = 41.132

biglilly
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thank u very much sir for such a big help it was very helpful for me because this is not in ncert book but in syllabus and it will be coming in 2024 board exam ❤

BLACK-qcyx
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Thank you so much sirr 👍
Ye question smjh hi nhi aa rha tha
Ab samajh aa rha hai🥰🥰

chanchal
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Sir hm aise nhi krsakte like..
Hm diameter nikalne ke liye (14-3-3)=8 nhi kr sakte kya??
Kyuki ye jo semicircle h un dono ke side me 3cm hai aur total h 14 cm..
To minus karenge toh diameter aajyega n?

Xyz
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sir i guess this topic is deleted from syllabbus .. isn't it?

omkapoor
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Exam ke ek raat pahle padhne wale aur ye soch rakhne Wale Aaj raat syllabus complete kar ke soige lekin 10 bajhe nidh aa jaye like me 11 March exam 10 March raat 9 .03 min par video dekhne wale like kare😅😅😅😅😅😅😅😅😅😅😅😅

iamahiranffid
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par ye vla topic to kta hai pr phir bhi sqp mai kyi aya hai

Dailyart
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Sir ya chap se kitna mask ka questions ata ha

deepbiswakarma
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Thankyou very much sir .
U explained this question in a very simple way which is easily understood

NikitaParida-oyvi
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Yeh question abhi mere preboard me aya tha😅

VISHAL__CHAUHAN
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Asa ques kabhi nhi ate the yeh ques phale years ma ate the like 2018, 19

imnoniteyt