Solving A Nice Exponential Equation | Real and Complex

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[adandap]

Cool. (But the end there you actually show the complex solution for n = 0, not n =1)

[mahdiali]

Please more example technique you are using when you are factarable quadratic it is new for me sir please please please

[andylee]

Hey we haven't had a "happy birthday 2u" in a while! 🥳🎂

[levskomorovsky]

And more. I solved the equation not with respect to (2/3)^x, but with respect to (3/2)^x.
I got two roots u =2, x = ln 2:ln 3/2, which corresponds to your solution, and the other : u = -1. It turns out that (3/2)^x =-1 = (2/3)^x. How is it?

[carlosbutler]

can this help you calculate cubic yards?

[cameronspalding]

I would have divided by 4^x to give a quadratic in 1.5^x

[cambrianhills]

Hallo Sy

I too wondered about the 4^1/2 being only positive; and the n = 0 and not a 1
Just curious 🙂


And as I have asked before can you please do the ln(a/b)’s numbers for us to see them and thus the eventual result.
Otherwise I have to do my these days calculator so
ln(2/3) is 0.693/1.099 = 0.631
and doing it log10 is, no surprise, the same ;-)

Anyway please do the whole thing to come up with the numbers, doing the arithmetic of course too.

Cheers

[tygrataps]

Early on, sqrt(4) is only +2 rather than +/-2. Does that change the end results in a meaningful way?

[rajeshbuya]

Nice problem! Missed 2z or Not 2z, despite several opportunities that existed!

[vizirudominic]

at 4:13 how did you get from (6/9)*x = (2/3)*x. Pls if not you someone respond to this comentary

[vladimirkaplun]

Can you solve x^2-3x+2=0? If so I give you much more complex one: 2x^2-6x+4=0. 🐒