Limit of sinx^2/x as x approaches 0 | Calculus 1 Exercises

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We evaluate the limit of sin(x^2)/x as x approaches 0 by multiplying the limit by x/x, then apply the limit product law to separate it into two easy limits. The first is limit of sinx/x as x approaches 0, and the second is simply x. Easy! #Calculus1 #APCalculus

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WrathofMath
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Thank you Much....I was having such a hard time with this & the Solution was a piece of Cake ❤️

xyco_edits
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I learn calculus on my own and used de l' Hospital. But good to see other ways too to get more varied and more in depth what can work too.

pianoplayerable
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For the x^2 I just did (x * x) and sin x/x = 1 then just did dirext substitution which is x = 0*1. Did I disobey any math rules?

doggy
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You can use L’hospitals rule to as you get 0/0 in the first direct substitution. This gives (2xcosx^2)/1 which equals 0/1 =0. Though in all honesty the squeeze theorem and product rule are fun too.

mooblerthomson
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Evaluate lim x -> 0 (sin x ^ 2 - sin^2 x)/(x ^ 4) Can you solve this sir

usthestarboom
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Can you explain about limit x^2 approach 0 ?

サバトラ-mn
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Now I wonder what sin(sqrt(x))/x goes to as x goes to zero?

alessandrorossi