Limit of sin(2x)/x as x approaches 0 | Calculus 1 Exercises

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We show the limit of sin(2x)/x as x goes to 0 is equal to 2. To evaluate this trigonometric limit, we need to remember the limit of sin(x)/x with x approaching 0, which is a fundamental trigonometric limit equal to 1! If we remember this, we'll be able to solve the problem in short order. #Calculus1

Proof for Limit of sin(x)/x: (coming soon):

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Help support the production of this course by joining Wrath of Math to access exclusive and early Calc 1 videos, plus lecture notes at the premium tier!

WrathofMath
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You're a great teacher, sir. My current Calc course does not seem to adequately cover fundamental trig limits like this. You've set me on a path to fill this gap. Thank you.

htothebeee
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I've been straining my brain trying to figure out why this standard limit was true and I didn't get it until you explained it. Thank you so much!

jerrarddoran
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I had a homework assignment with this problem on it. I was stuck so I searched it Uop and this was my first result. Thxs so much!

samuelzhao
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For small values of x, sin(x) is approximately x. So sin(2x) is approximately 2x. So we get roughy 2x/x = 2

Alians
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Great explanation and lovely setting. Thank you very much!

RickRudy
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THANK YOU WRATH OF MATH YOU ARE THE GOAT

TheDealIsDivided
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Thank you so much! you made it a piece of cake!

Maryam-cdbq
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what if instead of x in the denominator its |x| (absolute value)?

iloveroblox.