Limit of sin(x)/x as x goes to Infinity (Squeeze Theorem) | Calculus 1 Exercises

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We use the squeeze theorem to evaluate the limit of sinx/x as x approaches infinity. This is easy as soon as we recall -1 is less than or equal to sin(x) is less than or equal to 1, then just divide everything by x! #Calculus1

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Help me produce this course by joining Wrath of Math to access exclusive and early Calc 1 videos, plus lecture notes at the premium tier!

WrathofMath
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appreciate this! very well explained :))

princessatellaluma
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How would you do the epsilon-delta on this? I can't come up with a way to prove the limit of sinx / x, but I can prove the limit of x / sinx pretty simply. Is it acceptable to do epsilon-delta on the reciprocal of a function, and then invoke the reciprocal rule of limits?

kingbeauregard
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You have managed to squeeze a very important lesson from this example! 😃

punditgi
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Lim 1/1+n sin^2(pi x), x tends to zero, please do it and send me

safiurmallick
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How can we fine Lim x approaches infinity x+sinx/x

GhazanfarAli-ofyt
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What if limit x--->0 ??.? For the same question

AmitaKumari-yqbd
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Is this following sendwitch theorem ... ?

about_nasa_videos
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You need to work on your calculus as the limit is 1 and not 0. Look at the graph you showed.

elviszavatti