Prove that Sum((-1)^n * (n choose r)) = 0

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Prove that Sum((-1)^n * (n choose r)) = 0. We use the binomial theorem.

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There is also a cool proof using Pascal triangle. For i+1 th level: first element of ith level will add itself to 1st and 2nd elements, of i+1 th level, 2nd to 2nd and 3rd, and so on. Every element of ith level will add itself to one element of i+1th level on an even postion and to one on an odd position, so sum of elements on even positions willl be equal to the sum of elements on odd positions, which is what problems asks.

timreizin
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First easy exercice of my Discrete mathematics final. Good start, easy points

SimsHacks
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I have a question. If n = 0, then wouldn't it be 0^0 = 1?

classic
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Are you using pencil? Shocking😱
I think I used pencil last time (8 years ago)

nikhilgond