Linear Algebra Example Problems - Subspace Example #3

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We work with a subset of vectors from the vector space R2. We show that this subset of vectors is NOT a subspace of the vector space.

In general, given a subset of a vector space, one must show that all of the following are true:

1) Contains the zero vector, 2) Is closed under addition, and 3) Is closed under scalar multiplication.

If any of these fail, the subset is not a subspace. In this problem we show that both 1) and 3) are not true, and thus the subset of R2 is not a subspace of R2.

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simple and concise, by the way i thought that scalar C should be an element of the same set, after reading your comment it is clear, thank you.

DavidMOUSSONGA
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Thank you so much!! I have a final tomorrow and this helps so much!

stephiediores
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Your videos are so helpful. Thanks for taking the time to create these!

travisl
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Very straight forward and easy to understand. Thank You!

adamali
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Does U violate the 2nd rule as well in this problem? Can it be closed under addition?

adam.kruger
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Sir thank you so much...sir can you upload the videos on INNER PRODUCT SPACE .concept...sir.

mathsgnr
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but in example 2 (previous video) you didn't choose any value for the scalar C, couldn't you make C = 1 and it will satisfy the 3rd condition?

amermurshak
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but [0 0] do have zero element and it is closed under addition and multiplication. Check the khan academy video they mentioned [0 0] is a subspace

PankajKumar-yggy
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one question, why did you pick -1?
or is the c not defined by x > 1

schotterfresse