Lagrange multipliers in three dimensions with two constraints (KristaKingMath)

Learn how to use Lagrange multipliers to find the extrema of a three-dimensional function, given two constraint functions. In order to complete this problem, you'll need to take partial derivatives of the original function, as well as each of the constraint functions. Then, you'll set up your equations in order to solve for two multipliers and the three variables from the original function. Once you've found values for the original variables, you'll plug those values into the original function. This will give you the value of a maximum or minimum of the function.

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Hi, I’m Krista! I make math courses to keep you from banging your head against the wall. ;)

Math class was always so frustrating for me. I’d go to a class, spend hours on homework, and three days later have an “Ah-ha!” moment about how the problems worked that could have slashed my homework time in half. I’d think, “WHY didn’t my teacher just tell me this in the first place?!”

[Marlowann]

You explain many steps that a calculus text would not go through such length to explain--- that is, you are patient and generous with taking your time to explain each step to illustrate the concept, even when you technically don't have to do so.

I am impressed.

[antonior]

you are saving my life for my exam tomorrow, honestly all I do in class is smile and nod, I didn't understand a single thing but your videos make it easy. the only thing now is that its a long process and my exam covers like 14 topics. I honestly just wanna pass. IDC. thank you!

[fudge]

This is great! I love how you don't do just a baby-example that looks nothing like my homework, but rather go through a tough one so anything else looks easy :) 

[Monllorf]

You take your time to excell, wish I had a teacher like you when I was young. I am retired after working for 35 years, my first job was as a Physics and Calculus teacher @ Croem 1972-1973 @ PR

[philn]

Much appreciated thank you. I had tirelessly searched for this specific example to no avail

[jamesarnold]

progressively better with each instruction. Again thank you!

[psalmistelnuvo]

I just love your voice and your charisma. I can watch your videos over and over again. Thanks so much Krista King.

[collegeguy]

said it before and will say it again, Krista you make math so much fun. I'm passing my engg courses because of you. Thank you for taking your time to do these videos

[kamrankhankami]

in this quarentine, you are the best teacher i
your voice is cool, I mean really cool, means cool in temperature, or the pitch because it doesn't hit the ears badly..
thank you for explanation

[vaibhavsingh]

Greatly explained ma'am....your explanation even 8years ago was so amazing....hats off ma'am 😀🎉👍🏻

[muraripanem]

It's really clear explanation.. thank you madam

[GenerationTheFall]

just wanna drop a huge thanks! i can't believe you took a concept which i've been stuck on and made it look soooo easy. i bet if i had found your video earlier on in the course i would have enjoyed maths so much more! thank you!!!

[j.rautio]

I was reading a book about Richard Feynman and at the point Lagrange was mentioned I had to Google it up to brush up my memory and I ended up finding your channel. Calculate the probability of that event ;)

[jadecarlson]

low-key this video just saved my life, wish you were my multi prof!

[meensbeans_]

My girl! You are amazing! Thank you for being so clear and precise 👌👌👌

[opolotmichael]

This has been a helpful video for me to prepare for my placement exams concerning LaGrange multipliers

[kunjaai]

I could refresh my basic maths.. thanks alot ...

[MukeshSharma-cliw]

Better explantaion I have found till now.

[andrewdenterlein]

Very clear explanation. These systems can get tricky, so I'm hoping the exam questions won't be too difficult. Thanks for posting!

[gayathrisunil]

Mam, can you please explain the method of the following question...
Find the starionary points of f(x, y, z) = x^3 + y^3 + z^3 subject to
the constraints
g(x, y, z) =x^2 + y^2 + z^2 =1 and
h(x, y, z) = x+ y+ z=0..