Solve the Exponential System of Equations | Learn how to solve this Question without anxiety

preview_player
Показать описание
Learn how to solve the given system of equations quickly.

Today I will teach you tips and tricks to solve the given olympiad math question in a simple and easy way. Learn how to prepare for Math Olympiad fast!

Need help with solving this Math Olympiad Question? You're in the right place!

I have over 20 years of experience teaching Mathematics at American schools, colleges, and universities. Learn more about me at

Solve the Exponential System of Equations | Learn how to solve this Question without anxiety

Olympiad Mathematical Question! | Learn Tips how to solve Olympiad Question without hassle and anxiety!

#OlympiadMathematics #OlympiadPreparation #CollegeEntranceExam
#OlympiadMathematicalQuestion #HowToSolveOlympiadQuestion #MathOlympiadQuestion #MathOlympiadQuestions #OlympiadQuestion #Olympiad #AlgebraReview #Algebra #Mathematics #Math #Maths
#MathOlympiadPreparation #LearntipstosolveOlympiadMathQuestionfast #OlympiadMathematicsCompetition #MathOlympics #SolveSystemofEquations
#SolvetheExponentialSystemofEquations #LearnHowToSolveThisQuestionWithoutAnxiety
#blackpenredpen #Exponential #Equation #OlympiadMathematics

How to solve Olympiad Mathematical Question
How to prepare for Math Olympiad
How to Solve Olympiad Question
How to Solve international math olympiad questions
international math olympiad questions and solutions
international math olympiad questions and answers
olympiad mathematics competition
math olympics
olympiad exam
olympiad exam sample papers
math olympiad sample questions
math olympiada
British Math Olympiad
blackpenredpen
olympics math
olympics mathematics
olympics math activities
olympics math competition
Math Olympiad Training
How to win the International Math Olympiad | Po-Shen Loh and Lex Fridman
Po-Shen Loh and Lex Fridman
Number Theory
There is a ridiculously easy way to solve this Olympiad qualifier problem
This U.S. Olympiad Coach Has a Unique Approach to Math
The Map of Mathematics
mathcounts
math at work
exponential equation
system of equations
solve system of equations
solve the equation
Solve the Exponential System of Equations
pre math
Po Shen Loh
Olympiad Mathematics

Subscribe Now as the ultimate shots of Math doses are on their way to fill your minds with the knowledge and wisdom once again.
Рекомендации по теме
Комментарии
Автор

Wow! Such a fantastic mathematical problem! keep going ❤
Much love ❤

jimmykitty
Автор

On substitution (7)^ab = 343=7^3 as such equating the powers ab = 3

ganeshdas
Автор

It is so nicely explained here.
It was looking to be difficult one.

salimahmad
Автор

Solved it in seconds, thanks for providing the problem

sigmamaleslogokijalegi
Автор

There is a small confusion in problem definition.
It is shown as 7a = 77 in youtube list.
However i solved it as 7^a= 77

sandanadurair
Автор

Amazing👍
Thank you so much for sharing😊

HappyFamilyOnline
Автор

Nice, keep going, 3 videos in a day u rock!!

srividhyamoorthy
Автор

V nice. A quick revision of exponents in simple steps.

nirupamasingh
Автор

realy a very nice problem. also we can take logarethm of both equations and calculate value of a &b then substitute in a.b=?

osamaalsatari
Автор

Done
I'm getting better practice for my exams :)

parikshitparekh
Автор

In a few compact lines: 7^a x 77^b = 77^1 x 7^3 (343=7^3) By correspondence, b=1 and a=3. ab = 3 x 1 = 3.

monroeclewis
Автор

Another solution is taking log both sides in both equations and getting value of a and b individually
Log 7^a = log77
a= log77 / log7.. eq1
Similarly b = log 343/log77.. eq2
Multiplying eq1 and eq2,
We get ab = log 343 / log7
ab = (3× log 7)/ log 7
ab = 3

ankurdwivedi
Автор

This is quite easy can solve it mentally to get the answer

Lolo-uzuy
Автор

Sir, plz include logical questions also.

sandipVR
Автор

Nice solution. I used the logarithmic way as follow: a = log7(77) which can be transformed as a = ln(77)/ln(7). The same with b: b=log77(343) = ln(343)/ln(77) Now we can fill in the blanks in a*b: a*b = (ln(77)/ln(7) * (ln(343)/ln(77) = (ln(77) * ln(343)) / (ln(7) * ln(77)) => ln(77) cancels out: a*b=ln(343)/ln(7) which can be transformed into a*b=ln(7^3)/ln(7) and then a*b=3*ln(7)/ln(7) => ln(7) is gone: a*b = 3 as shown in your video.

dreael
Автор

7^a=77
77^b=7^3
77= 7^3/b raised both sides to the 1/b
7^3/b =7^a
3/b=a
3=ab Answer

devondevon
Автор

Shouldn't it be 49^ab instead of 7^ab??

cp_driftr
Автор

I solved another difficult way.😂 (11×7)^b÷3=7. However your method is very easy and thank you for your help.🤩

sriyanijayarthna
Автор

excellent presentation, great job solving this exponential system of equations

math
Автор

Nice


Very simple but common people became puzzled 🐒🐒🐒🐒🐒🐒

susennath