Techniques For Solving Logarithmic Equations (More Examples)

This lesson shows some techniques for solving logarithmic equations. This lesson was created for the MHF4U Advanced Functions course in the province of Ontario, Canada.

[MegaSquiff]

Simply excellent!...a great big thanks and please keep them coming.

[austintoh]

Thank you very much!! I have difficulties learning logarithms and you made it look so simple!! thanks!

[chandiliers]

I'd be lost without this guy. Thanks! My daughter will also thank you one day.

[Daddy-R]

What an excellent guy 👌🏼👏🏻 thanks for this video

[dizzychaseradio]

All great videos. Very helpful. Thank you.

[AdityaShinde_]

Wonderful!
I can suggest general mistakes in LOGARITHMS..
#DefinationsForStudents

[MysteriousStranger]

Thank you so much, I've been struggling in my A-level pure mathematics until now.

[MandaNovokmet]

Thanks so much for the video!! Extremely helpful; my friends and I feel ready for our test because of you!

[km]

Nice presentation....a variety of different examples and NOT so tedious as to discourage any student having trouble with logs from attempting to find the solution.
Too many times in some Precalc or Colleg Alg courses, the setup equations are so difficult to understand for struggling students (logs w/ different bases, etc.), that they just will not attempt to solve the equation. After all--one can't assume that everyone is an M.I.T. type..

[AlRichards]

Sorry, I must have missed this comment/question. log(1/3)9 = x so (1/3)^x = 9. 9 can be written as 3^2 since 3^2 = 9 then (1/3)^-2 = 9 so the equation becomes (1/3)^x = (1/3)^-2 so x = -2.

[missmeek]

please i need your help to solve this question.calculate TRY TO EXPLAIN THE STEPS FOR ME THANKS:

[estelleferreira]

Please help!!! My sum is 2log(3)x – 3log(2)4 = log(b)1. The brackets are the base

[AerisVera]

Solve for x (3^2^x)+ (4^(x+a))=1 I need a technique for this sort of problem.

[tuan]

log(1/3)^9 = x

(1/3)^x = 9

x = -2