Logarithmic Equations

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This math video tutorial explains how to solve difficult logarithmic equations involving exponents and square roots.

Log to Exponential Form:

Change of Base Formula:

Change of Base Log Problem:

Properties of Logarithms:

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Expanding Logarithmic Expressions:

Condensing Logarithmic Expressions:

Natural Logarithms:

Solving Exponential Equations:

Exponential Equations - Quadratic Form:

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Solving Logarithmic Equations:

Graphing Logarithmic Functions:

Graphing Exponential Functions:

Compound Interest Word Problems:

Logarithms Practice Problems:

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Final Exams and Video Playlists:

Full-Length Videos and Worksheets:

Logarithmic Formula Sheet:
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not talking about this video but this is the most recent one


you are amazing you saved my grades
- A high school student from Egypt

AxelTravix
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MR. Organic Chemistry Tutor, thank you for solving Logarithmic Equations and also checking the final solutions for extraneous roots.

georgesadler
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U made me passing my Calculus exam after failed many times!

abdelraouftria
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JG: a
Me: perfect! u did it again! thanks for helping me a lot, u rock

gabeugenio
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my first thought seeing the thumbnail

Hi, Im Presh Thalwalkar and welcome to ....

inferious
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Ever since I started watching your videos, my grades are always the way I want them to be❤❤❤

Blxckexcellence
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Thought I'd try this on my own.
By the reverse power rule the equation becomes 2log x = (logx) times (logx). Dividing by (logx) i got (logx) =2. 10^2 =100.
X=100

bobwineland
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Hi sir
Billion tks sir for solving my long outstanding question about these types of problems
I salute you sir

glasssmirror
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i really needed this last week, but thank you!

Krazyrayglitter
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I’m so confused with this math, it’s confusing, but I want to learn it, how are you coming up with these answers. Lol..

Belladorphia
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Hi love your videos bro. You really help ed me literally everyday with organic chem. Please reply if your are seeing this

ankitkumardubey
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How do you convert a negative log to an exponential. Where does the negative go

kaco
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I have solved both the sums on my own I am very happy

niranjanhalderb
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Tomarrow my maths exam of polytechnic in Eletrical br.

Knowledge_fact_VTT
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Log x + log x= log x *log x
=Log x(1+1)=log x*log x
=>log x=2 or log x =0

waynehuang
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Please, upload a video about " line jntegral "

fahad-
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So (log x)^2 = log(x^2) , couldn’t you just do
Log x times log x=>
log2x is that makes
Log 2x = 2logx which when you divide by log x =>
Log 2x - x = 2 which is only one of the answers what did I miss, seems like if I dropped the 2 from x^2 I need to account for it being positive or negative e but can’t figure it out.

zissler
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What's the difference between log x^2 and (logx)^2

artiskey
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at 7:52 how can it be how did it become 1/4 why not 1

sanopann
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sure you are a life sever




🥺

seblewongelminlargh