Physics, Torque (4 of 13) Force Not at Right Angle to the Object

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Shows how to calculate the torque produced by a force that is applied at an able to the object.

Torque is a rotating force. It is a measure of how much force is acting on an object that causes the object to rotate. The object will rotate about an axis, which is called the pivot point. It is labeled with the letter P or O. The distance from the pivot point to the point where the force acts is called the moment arm or the lever arm. This distance is labeled with the letter r. This distance r is also a vector, and points from the axis of rotation to the point where the force acts. The force is labeled with the letter F.

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It doesn't matter which angle because either one will get you the same value cuz sine of supplementary angles are equal

Warlord
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thank's sir i really appreciate it 😁

EnglishwithBilal
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I know that r is the distance in metres between the pivot point and wherever the force is applied, but from 4:07 to 4:35 I still don't understand your explain as to why r = 0.7 m and not 0.8 m... I also don't understand what you mean by 0.1 m from the end of the door despite looking at the image

annikaj
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what does that mean for torque to point perpendicular to the force applied? is torque an opposite and equal reaction? what can torque do?

hopolo
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Can use either 130 or 50 degrees, as sin(130) and sin(50) both give 0.7664 approx. It makes more sense for me to use the angle between the beam and the force

masonkaehne
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Currently learning this in my Mechanics class! Thank you for this thorough course!

Lexyvil
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Is 'F.sin(theta)' just the perpendicular component of force from the radial vector? Is this just a distance using pythagorean theorem?

kaiok
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Why couldn't you use 50 degrees as your theta as well? You would get the same answer.

nadermohamed
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you helped me cram for my midterm, i love you

Quickyy
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The torque is exactly double the area of the triangle made.
Area of that triangle = 77*sqrt(3)/8
Area of torque = 77*sqrt(3)/4

thomasolson
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One hour left before my final. This is great reviewing~

Lexyvil
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this was extremely easy to follow and well explained. I understood everything! BUT my physics professor (as well as many others) use the term "lever arm". And that Torque = (Lever Arm) x (Force Applied). Sometimes, the length of the lever arm is derived as the"line from the axis of rotation" that runs perpindicular to the "line of Action". My professor prefers the usage of this equation, and claims it can be derived utilizing trig functions. My question is, in this case; would "cosine" be the trig function used when the angle is between the radial line and the lever arm? thanks

poisonedcheeseproductions
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why is the angle at 1:57 130 instead of 50?

markwu
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These are really good thanks you so much. Better then my physics teacher :))

MonolithPvP
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I am confused in how picking the angle to use for theta. Is it always gonna be the angle away from the pivot?

lauralc
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My lecturer taught me that theta is the angle between the radial vector and the applied force..

syafiqttu
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thank you so much for all of your videos <3

kelseyn