Physics 15 Torque Fundamentals (5 of 13) How to Calculate a Torque (Method 2)

preview_player
Показать описание

In this video I will show method 2 of 3 of calculating torque = (force) x (perpendicular distance).

Next video can be seen at:
Рекомендации по теме
Комментарии
Автор

Hello,
How would you conclude that the given angle theta is the same as the angle next to the pivot point?
+1:40

shubhamsingh
Автор

But the object tends to rotate in a clockwise direction isn’t torque suppose to be (-69) ?

Tugba.aydinn
Автор

I think you meant 69 N.m for the final result..
Very helpful videos. thank you so much Mr. Biezen

alandaleb
Автор

Thank you so much for doing these videos, so helpful

stealthcatfood
Автор

we used to calculate the torque using the cross product of f x r sin theta but you are using the cosine ! why

منوعات-تف
Автор

Thanx helped a lot but a question why did you use cos and not sin cuz it's supposed to be cross and not dot when we use the torque we use cross not dot which leads to using sin not cos am I right or...? Cuz it says cross in my book

haluushi
Автор

Sir i ask one question why not make d = L sin . because sin is also opposite÷hypotunius , how do you know this cos . The base & perpendicular, how do you know, ?hypotinius i can find easily .

JeevaAjay_