Physics 15 Torque (4 of 27) Bar Held Up by Friction

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In this video I will find F=? (rod) and T=? (cable) of a system of a rod resting off the ground with a cable attached on one end and hanging off the ceiling.

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Dear Professor, i think in time 7:00 of the video, you forgot to put parentheses around mgx + mgL/2. Am i right?

RiaziMohandesi

Wouldn't the distance to the pivot point A of T be just the whole length of the bar? Since only Tx is the one acting on point A and both Tx or T have the origin of the vector at the end of the bar?

tfos

Could we have maybe assumed that x was just some coefficient times the length thus letting us cancel out all the L's in the sum of torques on A ? This is the way i tried to solve it before watching the video and i have a feeling that my reasoning is somehow wrong.

frnchdazzled

In Fk computation, both two terms of numerator must be multiplied by mu * cos(20deg.).

hidetsuguhiraki

Dear Professor, I would like to know how X component of T is considered as a frictional force. Shouldn't be it as Ty? F(friction = Tsin20xmu ) is correct?

vanitavaria

Hello professor, from questions that ive answered in the past, when the bar is being tied to the wall, shouldnt there be a reaction force opposing the tension from the wall to the bar since the bar is being pushed to the wall? I couldnt answer this question because i included reaction force so i wonder why we have to exclude the reaction force in this situation?

mitachurl

The solution is incorrect. The factor cos(20) in the expression for the friction force is multiplied by the entire nominator, but in the calculation phase you multiplied it only by one of the terms in the nominator. The final answer should be 34 cm, not 20.7 cm.

dariosilva

How did you know where to choose the pivot point at?

oishikachaudhury

Why does the Tension NOT cause a torque about point B?

Asrahi

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