n Choose r | Combinatorics | Mathematics Olympiad | Grade 8 -12 | IOQM 2023 | Abhay Sir | VOS

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[saptakghosh]

Solution of the HW question:
No. of paths from A(0, 0) to (2, 3) = 5!/2!3! = 10
No. of paths from (2, 3) to B(4, 5) = 4!/2!2! = 6
Total no. of ways to go to B from A = 6*10 = 60👍

*** first comment

[nikhiljha]

Hw. Ans.
Total no. of ways going to X from A
5C2=10
also no. of ways of going to B from X
is 4C2=6
Therefore multiplying both jobs we get 60ways

*3comment

[srishtisaraswat]

Sir HW question ans

By taking rectangle with vertics (0, 0), (0, 3), (2, 0), (2, 3)
No of possible ways to go from A to point (2, 3) are =⁵C3=10

By taking rectangle with vertics (2, 3), (4, 0), (2, 0), (4, 5)
No of possible ways to go from point (2, 3) to B are =⁴C2= 6

So clearly no of ways to go from A to B are = 10×6 = 60 Ans

[raunakverma]

1:13:40, Le my mom- Beta Mai maths teacher ho ullu Mt bna😂😂

[AryanMishra-sz]

sir in the previous video I couldnt even solve a single problem but as I tried doing on my own I solved the questions of this lecture with ease !!!! becoz I didnt give up rather I enjoyed every problem with feel

[shalvagang]

Sir thsi means that the last question was jsut the inverse of that we do if we have an inewuality of x+y+z<900 we introduce a dummy variable. Ut here we just divided it

[Akshat-st]

Solution of HW Question-
No. of ways of going from A to X = 5 CHOSE 3 *1= 5!/2!*3! => 10
Now, no. of ways of going from X to B = 4 CHOSE 2 *1 = 4!/2!*2! => 6
through Fundamental Principle of counting = No. of ways of going from A to B (shortest ways) = 10 * 6=

[rishabhsolanki]

In the last questionm What was original written was correct. It should be 6 instead of 10. As a, b, c, d should also be factors of 30 (2*3*5) powers of 2 in either of a, b, c, d cant be greater than 1. So the case 2 0 0 0 cant be possible.

[Surendra.]

Sir please start algebra ... specially on functions....

[mithusaha]

@50:00, sir how can you say all are rectangles?,

If I take 2 and 5 from the vertical side and 3 and 6 from the horizontal side, it makes a square of side 3 units, so there a many such squares inside all the recatngles counted


Sir please solve my problem

[shalvagang]

Solution to HW question ways to go from a(0, 0) to x(2, 3) if you see the no of ways to go from 0, 0 to 0, 1 is exactly 1 and no of ways to go from 0, 0 to 1, 1 is exactly 2 if you can see a pattern is generated that the no of ways to go from 0, 0 to any point is the sum of the ways of going in adjacent column so ways to reach x(2, 3) is 10 and from then we start recounting then we get the same pattern so th no of ways to reach is 4, 5 is 6 so the no of ways will be 6*10 by multiplicatio. Principle


Second comment

[aryanmishra]

Sir l solved most of the questions with ease ❤😊😊