First Law of Thermodynamics, Basic Introduction, Physics Problems

This physics video tutorial provides a basic introduction into the first law of thermodynamics which is associated with the law of conservation of energy. There are two main ways to change the internal energy of a system - that is, through heat and mechanical work. This thermodynamics video tutorial contains plenty examples and practice problems on heat, work, and internal energy calculations.

Physics Video Lessons:

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Open Vs Closed Vs Isolated System:

Isobaric Process:

Isochoric Process:

Isothermal Process:

Internal Energy of an Ideal Gas:

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Adiabatic Process:

PV Diagrams:

Thermodynamics Review:

2nd Law of Thermodynamics:

Heat Engines:

Converting Heat Into Electricity:

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Carnot Cycle:

Otto Cycle:

Refrigerators and Heat Pumps:

Entropy:

Heat Engines and Refrigerators Review:

Physics PDF Worksheets:

[strangeperson]

When I get my degree it's going to look like I got it from the University of The Organic Chemistry Tutor! Lol <3 :)

[jstroner]

Thank You. You are the smartest man on YouTube by far.

[donwalegere]

Thank you, as a grade 11students taking science class I learn so much from you.

[okaforcaritas]

U are really good… u have done two videos regarding this topic for physics and chemistry (view point from the surrounding and system) and u never contradicted urself… most textbooks contradict themselves

[matrixate]

For the record, and as a note to myself, in example 1, the work done BY the gas should be looked upon as a decrease of internal energy used to cause the piston to move, in this case, up. So while you were probably taught that work done by a gas is negative, it depends what version of delU you're using. If it's U=Q+W, the work by the system is negative to represent that the system is consuming energy to cause motion in which case you plug in a negative quantity, whereas, in this example, the negative is already there and thus since work is Fd, and the direction of the motion of the piston is in the direction of the Force applied, then work is....positive. Right. So, work is positive in the equation that represents positive work done by a gas, hence U=Q-W. If this makes sense, great, but it does to me...rather, this is the way I see it.

[meera]

You r multi Skill person..(science, Physics, chemistry, Electrical, Mechanical) Great😎😎😎

[ma.patimarempis]

My teacher taught me when work is positive it is done by and if negative done on.

[soretimekbib]

U ar my best teacher to all calculation need subjects i really thanks u my life saver

[yct_keera]

1 month to my final examss and you helping me alot thanks 😊

[TheJProductins]

I'm taking this class next semester (Electromagnetism and Thermodynamics). I want to study ahead during winter break. Could you point me to your videos that will help me for the first few weeks ?

[leakry]

I like it very much. The first low of thermodynamics is good for me that I want to research and learn more about the fluid of mechanics.

[johnpaulreyes]

Thanks Sir I learned many things so much from this video .Have a nice day 🎉❤🎉

[terryivinho]

Great work BTW. but It would be nice if you put if the pressure was gauge or absolute in the last question .

[NGOMALYF]

6:58 i think if its constant pressure then h=q-w then you can find u from h=u+pv

[JohnRhynzMLasac-zqsi]

Thanks you I can now answer my Science

[akinapallydeepika]

Sir in 3rd question, they also gave " on the gas ", so then we get the value as -1350

[netsanettirusew]

My teacher taught me when work is positive it is done on and if negative done by

[aaska]

I think the work in the 3rd question should have a minus sign because gas expands so the system (the gas) is doing work which means energy is lost by the system to its surroundings in the form of work hence the minus. I might be wrong but you should check out that question again, just saying...

[retsepilemothepu]

My Physics improved from 50% on semester test 1 to 97% on semester test 2🎉🎉
Thank you sir, I have nothing to offer. I’ll thank you properly in the future.

[turkishandmore]

I have some doubts though
Work equals to the integral of Pressure as a function of Volume and not Pressure multiplied by Delta V in the first place, since dW equals to PdV