Physics 3.1: Projectile Motion on an Incline (1 of 7) Example 1

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In this video I will find the height and the distance traveled on the incline of a projectile fired from a cannon at an angle theta=50 on an incline of phi=20 with respect to the horizontal.

Next video in this series can be seen at:
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lol. whenever i watch your videos i pause it as soons as it starts and try to figure it out on my own. i spent 20 mins trying to figure it out and gave up feeling then you added an initial velocity 30 secs in :P

augustmd
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Thank you so much I had a similar problem and this summed it up way better than the textbook solution could

genosmrpg
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can you kindly make video where the object is launched above the ground. where the initial velocity is unknown please!!

livingstoneluneta
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I got this problem but the excercise only gave me initial
Position and the angle what do I do ?

tracksam
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Can you just subtract the angles and treat it as a flat surface?

jengabeans
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Sir please upload Required angle solution for incline projectile motion

shadannawawng
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hey u made it complicated.... why dont you remove that inclined plane and take angle 70 degrees and find time at given point x, y ... where x= dcos20 and y=dsin20...

syedsameerphysics
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What about the maximum height the projectile achieves above the incline?

schrod
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Small mistake at 9:00 ! It's supposed to be 62.82^2, not 66.82^2. Does not change final result after rounding but thought I'd point it out for anyone who didn't get the exact same result :)

skursh
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Professor sir i have a doubt when you find t in air with x direction then that time you said there is no any force on x direction so acceleration will be zero right so it is absolutely clear but can any case be happened where force is not zero in x direction 🤔🙄 plz clear my doubt . Btw thank you so much for attend my last doubt ❤😊

PrinceKr-xk
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Whenever I watch your videos I feel inspired!! Thank you so much! More of the same please

cowgate
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Some short stuff I found on textbooks

D=(2)(Vi²)cos(proj angle)sin(proj angle-incl angle)/(g)(cos(incl angle)²)

T=(2)(Vi)sin(proj angle-incl angle)/(g)(cos(incl angle))

Would these be "just the same/interchangeable" to what you did? I find myself really slow on these

sirduckoufthenorth
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What if an object is fired on the ground and land on incline?

leo_lcw
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why isn't the angle for both expressions 50? it is the total angle of the 'launch' isn't it??

lollabytaskmaster
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good video save my physical homework in utsc

sworddark
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I dont understand why the acceleration along X is zero. Isnt it decelerating along the x as well?

mashvill
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why are you using horizontal displacement of the projectile to be 86.6 metres instead of 100 metres please clear my doubt

umairkhan-sism
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BEST ON THE INTERNET-- I HAVE UNDER STOOD

kaursingh
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This is a very cool problem! Thank you for explaining it accurately

qwertytwerqy
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How do you calculate that particular case if you only know that the angle of the hill is 45 degrees and you need to find a launching angle at which we throw the ball uphill (ball bounces off the hill once so that it comes back down to the starting point)?

TheDevilHimself