Projectile Motion: Finding the Maximum Height and the Range

Physics Ninja looks at the kinematics of projectile motion. I calculate the maximum height and the range of the projectile motion.

[metiburussie]

If only our professors/teachers could be as crystal clear as you! Thank God for your brilliant mind. Keep up the excellent work.

[lacertus]

Wow, you saved my life. I’m forever indebted to you.

[jessamaecabizares]

Thank You so much for making this video. It really helped me in my online class, especially self study is not easy. Thank you for sharing your ideas that is very clear and so understandable. God bless and more power!

[lukaround]

Great Job, thank you. Trying to explain it to my son and came across this video. It reminds me of my teacher

[torilecky]

This is in fact the single most helpful video on the internet. Thank you.

[lillycrochet]

Thank you so much! This video really helped me see the breakdown of the equations used to find the specifics (time, max height, vertical height, etc.) Please keep making videos and thank you :)

[MathPhysicsEngineering]

If you are interested in an in-depth analysis of the geometry and the physics of projectile motion I recommend:

[burgamin]

First video about this subject that I actually understood, and, more importantly, learned something new!

[donsolellizekristine]

Thank you so much! the explanation is very nice and smooth thank you again sir have a great day ahead

[nirupamam]

I understand everything you said because you know how to reach us😊😊👍👍

[iRobotray]

This is the best projectile motion video of all time

[lilac]

Such a lifesaver! Better than my professors

[dannydeko]

Every time I thought "why is he doing that??" you explained it perfectly.

[dylaninho]

Great vid, in the last equation you can simplify 2 sin theta cos theta to -> sin2theta

[emersonbatzin]

This video made the concept so much easier, i get it now

[ayushagrawal]

Thanks alot sir, excellent way of explaining complicated stuff...

I had huge doubts in projectile motion, i looked at many videos but only found this one useful and best...

[vanessachen]

thank you for your effort, patient and very precise explanation.

[merawithoney]

The video is really helpful, thank you. But I feel like it would have been more clear if you used numbers on your examples, and can the final range formula be further simplified into (v initial^2*(sin teta*)2)/g because I assume the angles will be the same?

[christinechoi]

Wow u are an amazing professor!! Easily understood

[HAL_HLA]

This 20 mins video is clearer than our 1hr discussion-