(Method 1) Integral of 1/(1-x)^2 (substitution)

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ะŸะพะบะฐะทะฐั‚ัŒ ะพะฟะธัะฐะฝะธะต
๐Ÿ’ฅ ๐ƒ๐ž๐ซ๐ข๐ฏ๐š๐ญ๐ข๐ฏ๐ž๐ฌ ๐…๐จ๐ซ๐˜๐จ๐ฎ

โœ… ๐ƒ๐ž๐ซ๐ข๐ฏ๐š๐ญ๐ข๐ฏ๐ž ๐ญ๐จ ๐œ๐ก๐ž๐œ๐ค ๐ญ๐ก๐ž ๐ฌ๐จ๐ฅ๐ฎ๐ญ๐ข๐จ๐ง

๐Ÿ™ˆ ๐’๐š๐ฆ๐ž ๐ข๐ง๐ญ๐ž๐ ๐ซ๐š๐ฅ, ๐๐ข๐Ÿ๐Ÿ๐ž๐ซ๐ž๐ง๐ญ ๐ฆ๐ž๐ญ๐ก๐จ๐๐ฌ

๐Ÿ ๐€๐ง ๐ข๐ง๐ญ๐ž๐ ๐ซ๐š๐ฅ ๐š ๐๐š๐ฒ ๐ค๐ž๐ž๐ฉ๐ฌ ๐ญ๐ก๐ž ๐๐จ๐œ๐ญ๐จ๐ซ ๐š๐ฐ๐š๐ฒ

๐ŸŽ“ ๐ˆ๐ง๐ญ๐ž๐ ๐ซ๐š๐ญ๐ข๐จ๐ง ๐ฆ๐ž๐ญ๐ก๐จ๐๐ฌ ๐ฉ๐ฅ๐š๐ฒ๐ฅ๐ข๐ฌ๐ญ๐ฌ

โœ๐Ÿผ ๐–๐ž๐›๐ฌ๐ข๐ญ๐ž

๐Ÿ’ช ๐‡๐จ๐ฐ ๐ญ๐จ ๐œ๐จ๐ฅ๐ฅ๐š๐›๐จ๐ซ๐š๐ญ๐ž
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๐Ÿšถ ๐’๐ญ๐ž๐ฉ๐ฌ
00:00 Use the 1/a^n = a^(-n) property
00:18 Substitution: u = 1-x
00:24 Differentiate in both sides
00:33 Substitute 1-x and dx
00:43 Take out the minus sign
00:48 Integrate u^(-2)
00:55 Rewrite expression
01:00 Undo substitution: u in terms of x
01:04 Add integration constant +C
01:12 Final answer!
01:17 See more!

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Hi I really love your channel you really helped me with integrals, but I wanted to ask if you have videos about how a rimman sum converts to an integral, I have a lot of trouble understanding how it works if you don't have videos about this can you please tell me where I can find a video that explains it well.
A big thank you again you are really helpful for every calculus student!

gabyshavit
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dx/{x+โˆš(xยฒ-1)}ยฒ
(Xยฒ-1) Whole in square root please

iceslice