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(Method 1) Integral of 1/(1-x)^2 (substitution)
ะะพะบะฐะทะฐัั ะพะฟะธัะฐะฝะธะต
๐ฅ ๐๐๐ซ๐ข๐ฏ๐๐ญ๐ข๐ฏ๐๐ฌ ๐
๐จ๐ซ๐๐จ๐ฎ
โ ๐๐๐ซ๐ข๐ฏ๐๐ญ๐ข๐ฏ๐ ๐ญ๐จ ๐๐ก๐๐๐ค ๐ญ๐ก๐ ๐ฌ๐จ๐ฅ๐ฎ๐ญ๐ข๐จ๐ง
๐ ๐๐๐ฆ๐ ๐ข๐ง๐ญ๐๐ ๐ซ๐๐ฅ, ๐๐ข๐๐๐๐ซ๐๐ง๐ญ ๐ฆ๐๐ญ๐ก๐จ๐๐ฌ
๐ ๐๐ง ๐ข๐ง๐ญ๐๐ ๐ซ๐๐ฅ ๐ ๐๐๐ฒ ๐ค๐๐๐ฉ๐ฌ ๐ญ๐ก๐ ๐๐จ๐๐ญ๐จ๐ซ ๐๐ฐ๐๐ฒ
๐ ๐๐ง๐ญ๐๐ ๐ซ๐๐ญ๐ข๐จ๐ง ๐ฆ๐๐ญ๐ก๐จ๐๐ฌ ๐ฉ๐ฅ๐๐ฒ๐ฅ๐ข๐ฌ๐ญ๐ฌ
โ๐ผ ๐๐๐๐ฌ๐ข๐ญ๐
๐ช ๐๐จ๐ฐ ๐ญ๐จ ๐๐จ๐ฅ๐ฅ๐๐๐จ๐ซ๐๐ญ๐
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๐ถ ๐๐ญ๐๐ฉ๐ฌ
00:00 Use the 1/a^n = a^(-n) property
00:18 Substitution: u = 1-x
00:24 Differentiate in both sides
00:33 Substitute 1-x and dx
00:43 Take out the minus sign
00:48 Integrate u^(-2)
00:55 Rewrite expression
01:00 Undo substitution: u in terms of x
01:04 Add integration constant +C
01:12 Final answer!
01:17 See more!
#integralsforyou #integrals #integration
โ ๐๐๐ซ๐ข๐ฏ๐๐ญ๐ข๐ฏ๐ ๐ญ๐จ ๐๐ก๐๐๐ค ๐ญ๐ก๐ ๐ฌ๐จ๐ฅ๐ฎ๐ญ๐ข๐จ๐ง
๐ ๐๐๐ฆ๐ ๐ข๐ง๐ญ๐๐ ๐ซ๐๐ฅ, ๐๐ข๐๐๐๐ซ๐๐ง๐ญ ๐ฆ๐๐ญ๐ก๐จ๐๐ฌ
๐ ๐๐ง ๐ข๐ง๐ญ๐๐ ๐ซ๐๐ฅ ๐ ๐๐๐ฒ ๐ค๐๐๐ฉ๐ฌ ๐ญ๐ก๐ ๐๐จ๐๐ญ๐จ๐ซ ๐๐ฐ๐๐ฒ
๐ ๐๐ง๐ญ๐๐ ๐ซ๐๐ญ๐ข๐จ๐ง ๐ฆ๐๐ญ๐ก๐จ๐๐ฌ ๐ฉ๐ฅ๐๐ฒ๐ฅ๐ข๐ฌ๐ญ๐ฌ
โ๐ผ ๐๐๐๐ฌ๐ข๐ญ๐
๐ช ๐๐จ๐ฐ ๐ญ๐จ ๐๐จ๐ฅ๐ฅ๐๐๐จ๐ซ๐๐ญ๐
Subscribe to Integrals ForYou
Watch, like and share the videos
Use SuperThanks in the videos
๐ถ ๐๐ญ๐๐ฉ๐ฌ
00:00 Use the 1/a^n = a^(-n) property
00:18 Substitution: u = 1-x
00:24 Differentiate in both sides
00:33 Substitute 1-x and dx
00:43 Take out the minus sign
00:48 Integrate u^(-2)
00:55 Rewrite expression
01:00 Undo substitution: u in terms of x
01:04 Add integration constant +C
01:12 Final answer!
01:17 See more!
#integralsforyou #integrals #integration
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