Geometry of Complex numbers | Lecture 6 | Application in Coordinate geometry problems | #2 SE

Geometry of Complex numbers | Lecture 6 | Application in Coordinate geometry problems | #2 SE

00:00 SE1: If a and b are real numbers between 0 and 1 such that points z1=a+i , z2=1+bi and z3=0 form an equilateral triangle, find a and b?

03:06 SE2: ABCD is a rhombus. Its diagonals AC and CD intersect at M and satisfy BD=2AC. If the points D and M are represented by 1+i and 2-i then find A? Support the channel:

[shay]

sir in question 1 i think we can also try it by equating the mods ie the sides of the triangle and they are equal, in 1st eq we get a=b rejecting negative value and in 2nd we get b2-4b+1 by quadratic formula we can get 2-root 3 and thus is also 2-root

[chiragatreya]

Sir but don't we apply rotation formula in anticlockwise sense then why should we consider +-??

[Binay_kr]

Sir isi ka 2021 ka answer ka video bnaiye

[anirudhsrivatsa]

sir at 0:59 you have written theta in e^itheta as +or- 60degrees, sir could u please tell how we can get two values there sir