Complex numbers : Finding Square roots of : ExamSolutions

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Tutorial on how to find the square roots of complex numbers.

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Because i equals the root of -1 and so when you square this you get -1... -1 multiplied by b squared gives - b squared. Take a look at my early videos on complex numbers to see these basic results for squaring, cubing etc for values of i.

ExamSolutions_Maths
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Thank you that was really helpful. Excellently explained, thanks again.

peterjhw
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I'm not sure. I just wanted an explanation on how to factorise those quartic equations that you did in this video

halimabegum
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i like the way u interpret the question

trkingdavid
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Do you have a video up on how to factorise quartic equations?

halimabegum
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Sir, may I know at the beginning part, how did you make that ...+b squared i squared reduced to -b squared?

chewphuiyee
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(a+bi)^2
=(a^2-b^2)+2abi
7-24i
So .. ab=-12 and
(a-b)(a+b)=7
a=-4, b=3 is a solution, as is a=4, b=-3.
i.e. -4+3i, 4-3i.

BossDropbear
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but if you substitute B= -5, +5 into the first equation (a^2-b^2= -21) you would only get a=2 right?

farshiddianat
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... if I may ask... why isn't b = +/- 2i one of the solutions ?

IShowAsutoro
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why does b have to be a real value 6:40?

lsmith
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b is a real number. For example 2i is an imaginary number but the 2 is real

ExamSolutions_Maths
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You sir are a legend thank you so much

prachinpatel
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if i want to find the square root of 1+root of 2 for example can i use a similar method?

APOSTASA
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why solution for square root of y must be real number ? 6:35 and 11:30

leetong
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e^ipi = -1, i^2ipi = 1, 4(e^2ipi) = 4

wdfomfg
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Can't believe this was uploaded when i was 10 years old

heishillary
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Why did the sign not change when the 21b^2 switched sides

bournelucid
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Sorry, my brother logged into my e-mail account and replied to this. Rest assured, I understood it. Well played sir.

dhvsheabdh
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but if you use b=12/a, the answer is ±(4+3i) instead of ±(4-3i)
does it matter? 
:) thanks

joycew
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Oh okay, and now i noticed i made a typo in the second statement :O that i should be an e....

wdfomfg