Square Roots of Complex Numbers

[mohammadibrahimkhan]

Mr. EDDIE, I am amazed by your way of teaching and want to know where you teach.

[ZonkoKongo]

I really like the content and style of your lessons, so I wanted to ask what kind of school system and grade that is? (Im from Europe/Germany)

[KurtDresner]

Would be cool to also show how this can be done in polar form.

[nicolasmarulanda]

i wish u were my teacher. u look like such a chill guy, but still cares for what students are learning.

[Jassajattvlogs]

Sir we can solve by this also a square = -8 and 2ab = 6 and we should use this formula a square + b square ka whole square - a square - b square ka whole square = 4 a square × b square so we can get the value of a and b

[manakmishra]

This kept boggling my mind, thank you

[trkingdavid]

i like the way you introduce the lesson

[andrewps]

Couldn’t you factor a difference of squares for a^2 - 9/(a^2) to (a - 3/a) (a + 3/a) or does this not help?

[andalibiftakher]

Awesome explanation but i have a question why didn't we just simply do this _+(-8+6i)^.5

[lenm]

why didn't we choose a's value as 3i by calculating the square root of -9 and assigning the value to a.

[liamtaylor]

I would have stuck with A level maths if you were my teacher

[RussellSubedi]

Even if you take a^2 + 9 = 0 as valid, you still get the same answers.

[wasimvillidad]

Hey Eddie, avoid quartics. a² + b² = 10 since Ιz²Ι = ΙzΙ² = Ι-8 + 6iΙ ∴ 2a² = 2, a² = 1, a = ±1 and so on.

[ryanlam]

It's kinda hard to wrap your head around a number that's not supposed to exist, but it does anyways