Find Square root of Complex numbers | Scientific Calculator fx 991 es

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[MatthewIbarra]

Thanks for the video! Clear and concise. Also, for those that are curious about the formula, it is pretty simple to derive when you represent the complex number in exponential form:

Let A = magnitude of a complex number, and theta = phase of the complex number:
sqrt( A * exp(j * theta) )
=> (A * exp(j * theta))^(1/2)

Using the laws of exponents to simplify:
=> A^(1/2) * exp(j * theta / 2)
=> sqrt(A) * exp(j * theta / 2)

Converting back to phasor form yields:
sqrt(A) ∠ (theta/2)

I like exponential notation in this case because it is easier to work with than rectangular notation, which can save you time on exams.

[mertaslanturk]

Thank you very much. Thanks to you, I was able to solve this problem that I have been dealing with for a long time. I hope you will always be very happy.

[yazeedalasiri]

Thank you, that was really helpful 🙏👍🏼

[AkashPramanik-bwte]

Thank you so much sir.This technique will greatly help me in my upcoming exam❤❤

[beast]

For God sake, i've watched this Video more than 100 times, , Everytime i understand it. But after a few week i forget it Again.. 😢

[shubhanand]

Can we use equation editor in cm1 exam from IAI ? Or not ?

[sofiamargarette]

Hello thank for this, I have a question, how about if its for cuberoot? Do I divide it by 3? And divide by 4 if rooted to 4?

[solimancedricgil]

may i askk? why the angle is being divided by 2 ?

[JohnDavidVillamil]

Hello what if the complex number is raised by 3/2?

[Lifewithcats...]

Please please please make a video how to find square root of a complex number using FX 991cw calculator

[aayushojha]

But it's only one root, what about the other root?