solving a HARD SAT rational & negative exponents problem

We will simplify this algebraic expression with negative exponents and also rational exponents. We will need to know the rules of exponents really well. This is a good but also tricky SAT problem because it tests on many rules of exponents. Remember when we have b^(m/n), it is the same as the n-th root of b^m and b^-n=1/b^n.

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"Just Algebra" (by blackpenredpen) is dedicated to helping middle school, high school, and community college students who need to learn algebra. Topics include how to solve various equations (linear equations, quadratic equations, square root equations, rational equations, exponential equations, logarithmic equations, and more), factoring techniques, word problems, functions, graphs, Pythagorean Theorem, and more. We will also cover standardized test problems such as the SAT. Free feel to leave your questions in the comment!
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#justalgebra

[davindersingh-dxnb]

All SAT questions you've ever solved here were quite easy. I need something difficult

[ryuga]

I just solved for x, like 2+1/3 = 7/3, so x⁷/³ will be x²√x, and the last option had this term, so that was it

[nnene]

why does it gives us the information that X and Y are greater than 1?

[equal]

Would've solved this in grade 7 tbh