Determine the moment of this force and the required force F

The handle of the hammer is subjected to the force
of F = 20 lb. Determine the moment of this force about the
point A.

In order to pull out the nail at B, the force F exerted
on the handle of the hammer must produce a clockwise
moment of 500 lb # in. about point A. Determine the

[crustyflamingo]

dude I owe you so much, seriously your channel has helped me so much

[EricCornell-qz]

Yes, I agree my friend. These videos help me to learn in such a wonderful way. Thank you so very much for your passion for education.

[InsanelyDusty]

how is the y turning it clockwise? if we just apply 20lbs of force in the y directs its ccw

[vutruong]

Can you help me ?
My teacher say (sin20) but I can't understand
+ MA = {–(100 cos 30°)N (450 mm) – (100 sin 20°)N (125 mm)}
= – 43.2464 N·mm = 43.2 N·m (clockwise or CW)

[farjamhaghighi]

the moments on x and y direction have different signs one is positive one is negative, why do we add them to find the total moment at A ? shouldn't we subtract? i got 21.81 CW

[corrinabeaven]

sorry, I am just a little confused. I notice that in the image the 5 in, or .416 ft is in the x direction, and the 18 in is in the y but when solving the problem you switched the two. I'm not sure if I'm interpreting the image incorrectly. But other than that, your videos are what get me through statics

[charliewilson]

I don't see why you took the Fcos of 18in? If COS is A/H then I'm thinking it's Fcos30(5in)?

[cloit]

I'm just wondering why there is a y-component acting at .4167 feet? Wouldn't the only y-force be acting at 1.5 ft and isn't the moment of that y-force 0 because it's acting along the line of the hammer handle? You're answer is obviously correct, I just dont understand why

[williamhaynes]

not pounds per inch.. you mean inch-pounds!!