Math Olympiad | Learn how to find the value of 7^(x-y) | Math Olympiad Preparation

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Math Olympiad | Learn how to find the value of 7^(x-y) | Math Olympiad Preparation

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I find it fascinating that the final answer is just an integer! Cool vid!

jorghimvenerablebosstein
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Even easier:
(7a+b)/(a+7b)=13/3
7a+b=13/3a+91/3b
(7-13/3)a=(91/3-1)b
((7-13/3)/(91/3-1))(a/b)=1
a/b=(91-3)/(21-13)=11

vitalistiknius
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11....divido entrambe le equazioni per 7^y...ottengo 2 equazioni la cui prima parte è uguale (a meno di una costante 13/3)...eguaglio queste 2 parti la cui incognita é proprio 7^(x-y)..

giuseppemalaguti
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Maravilloso Profesor, Maravilloso
Gracias por sus enseñanzas

luisalfredonarvaeznarvaez
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250 likes ❤️❤️❤️❤️🙏🙏🙏🙏🙏🙏🙏 extremely beautiful sharing ❤️🙏🙏🙏

zplusacademy
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The √7 factor on the right hand sides is inconsequential because the solution depends on the ratio of the two equations. It could have been √71 or π or anything (except 0) as long as it was the same in both equations; it cancels itself out.
The equations can be rewritten:
7ʸ(7.7ˣ⁻ʸ + 1) = 13√7 ... ➀
7ˣ(7.7ʸ⁻ˣ + 1) = 3√7 ... ②
Dividing ② by ➀:
7ˣ(7.7ʸ⁻ˣ + 1) / 7ʸ(7.7ˣ⁻ʸ + 1) = 3/13 ( the √7 factor has gone)
Putting u = 7ˣ⁻ʸ :
u(7/u + 1)/(7u + 1) = 3/13
⇒ (7 + u)/(7u + 1) = 3/13
⇒ 91+ 13u = 21u + 3
⇒ 8u = 88
⇒ u = 11

guyhoghton
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Yet another brilliant video - thank you

davidfromstow
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Solved without: a= 7^x; b=7^y.
7^(x-y)= 11

alexniklas