Prove Trigonometric Identities Part 2

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This lesson shows four examples (1 in part 2) regarding how to prove trigonometric identities. This is the second part of a two part lesson. This lesson was created for the MHF4U Advanced Functions course in the province of Ontario, Canada.
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I'm not 100% sure what you are asking, but perhaps this is it. In the LS part from the first to the second line the cos^2 x + sinx cosx factors into cos x (cos x + sin x). This is factoring a cos x out of the denominator. Remember that cos^2 x = (cos x)(cos x). Hope this helps.

AlRichards
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Check out my playlists or the site listed on my channel page which lists most of my videos by course in Ontario. I do have a Binomial Theorem video and several on Logs, but I'm not sure what you mean by indices.

AlRichards
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I'm assuming you are referring to example 4. Sinc e the numerator cos^2x - sin^2x factors into (cosx - sinx)(cosx + sinx) I'm looking how I can get one of those factors to divide out and noticing that the denomiator is cos^2x + sinxcosx I see there's a common factor of cosx in the denominator so it factors into cosx(cosx + sinx). Then the cosx + sinx factors divide out.

AlRichards
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Do you have videos on Binomial expansions, Indices and Logarithms?

MrElitegamer
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@sumtin1617 If you are asking whether this is an identity, it is not.

AlRichards
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Omg you make it seem so easy!!! Dx I'm terrible at these sort of things.

ssweetssammi
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Sir video is very fruitful really I got material from this video that I needed ...
One thing I would like to share is that whenever you are starting video please don't start by saying in this video again or this is question 4.because viewer may be interested to take this example as their first example..that I experienced today .. thanks

gulfamnazir
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can i know where is the Cos^2 from>>cos^2x+sin x cos x

GeraldDelMundo
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is proved
much easy than i thought
cross multiply them
do the cancellation part
make the denominator cos^2x
write sin in terms of tan
then make cos as sec
you r done with

AmritMega