Calculus 2 - Integration: Finding the Area Between Curves (5 of 22) Ex. 5: y=(1/4)x^2, y=x

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In this video I will find the area between the 2 functions y=(1/4)x^2, y=x.

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i can't adequately express in words my gratitude for your videos, or praise for their quality.

tiberiusG
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Thankyou so much for clearing my concepts ❤

harrasmansoor
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Thanks, I am hoping an exercise like this comes to my exam

edzifer
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I'm from Bangladesh.Thank you sir

sk_ismail_hsn
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I took my dA horizontally and got 40/3. Please tell me what I did wrong.

After integrating, I was left with [8y^(3/2)/3] - [y^2/2] from 0 to 4. I know this way seems much harder but in the end they should compute the same answer, correct?

sydniadams
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Very well explained, but a little messy...

wanderleyapparecidovieira