Calculus 2 - Integration: Finding the Area Between Curves (13 of 22) Finding the Limits of Integral

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In this video I will find the area between the 2 functions y1=x^3, and y2=x.

Next video in this series can be seen at:
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Your video should have more views and likes.

ScottNguyenRCAC
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My exam is tomorrow and this saved my life.

arjunchandgude
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@Michael van Biezen, shouldn’t the quadratic equation have its zero points at
(0, 4), instead of
(0, 2)?

My logic:
If you let y be equal to 0, you can factorize the equation into
0=x*(x-4) or
0=x and 0=x-4

Resulting in y being 0 at x=0 and x=4.
Checked it too with a solver.

Thank you in advance for taking your time to help!!

tms
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x equals 0 and x equals 4, not 2 as you stated on the parabola at 5 minutes into the video

mikekastner
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Dude your y=x^2-4 is incorrect, you're a bad robot. The -4 indicates that you should start the parabola lower at (0, -4). Please respond, thank you.

lillyzegarra
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But some of the area is negative doesn't that mean you're finding the net area not the total area am I right

r.m
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Why is there no plus c when you integrate?

cosmicbeth