How to find horizontal asymptote, vertical asymptote, & removable discontinuity (calc 1 tutorial)

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This calculus tutorial helps you to learn how to find the horizontal asymptote, vertical asymptote, & removable discontinuity. For H.A., we take the limit as x goes to infinity. For V.A. we pay attention to nonzero/0. For R.D. we pay attention to 0/0.

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#blackpenredpen #math #calculus #apcalculus

Horizontal Asymptote, 0:10
Vertical Asymptote 4:16
Removable Discontinuity 6:47
The graph 10:03
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It's been over 25 years since I've done calculus. However, every time I watch this show, I am always amazed at it's power. Even more amazed at the simplicity of how it is taught by this professor. I truly love your show.

arequina
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Great video! I often feel that there’s a disconnect between teaching the theory of limits and actually calculating limits. In this video you made a really good job combining the two. Made me go ”ahaaa!” a few times. :)

MrFedX
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This video was a great help! I couldn’t figure out what the difference between a vertical asymptote and a removable discontinuity for the life of me!

leronm
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I just love physics more and more when i see your videos

farespasuni
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What about oblique (diagonal) asymptotes of a function? Just curious, thanks for any responses :)

Chiinox
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thanks for the refresher, i'm starting uni next monday!

willful
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I remember learning about HA and VA in pre-calculus in college. Fun times!!!

ThePowerfulOne
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Nice Video! Just in time for final exam period for many students taking summer term!

nuji
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How about the third kind of asymptotę: y=ax+b?

snejpu
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Hey man great video, could you make one proving that π is irrational?

joso
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That blows my mind that (3x-6)/(x²+x-6) and 3/(x+3) have different values at x=2. The are equivalent formulas because you multiply the top and bottom by the same thing. But not really?

JefiKnight
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Thankyou now i ferfect the quiz because of your video

johnadrias
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can u do a video on finding asymptotes in case of polar coordinate system?

si
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Could you do a video on sketching rational function?

matthewstevens
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I’m a little perplexed as to why you didn’t just factor the top and bottom and cancel the (x-2) in the first place. To me it makes the whole problem easier.

JeffreyLByrd
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So, here's a fun (and probably difficult) set of questions: It's known that hyperbolic functions have sloped asymptotes. But is it possible for a function to have a non-linear asymptote? If yes, can you cite and demonstrate an example? If no, is there a proof that you can cite and demonstrate for it? :)

calyodelphi
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عفوا ..هل تستطيع اعطاء دروس جامعية ام لا ؟

Sainep
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Can u find the asymptotes that limits us to approach each other? yes its the internet

herowise
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That last part I did LH quickly in my head to find 3/5 lol

ligleaper
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The function f(x) = (3x-6)/(x^2+x-6) doesn't have a removable discontinuity at x = 2. It is defined there and it is continuous there. As you demonstrated in the video, f(x) = (3x-6)/(x^2+x-6) = 3(x-2)/((x+3)(x-2)) = 3/(x+3), so f(2) = 3/5. It would be a removable discontinuity if f(x) were defined in a piecewise way such that f(x) = (3x-6)/(x^2+x-6) for x =/= 2 and f(2) was equal to something other than 3/5.

charlottedarroch