If x+y+z=8 then xy+yz+zx=20 then prove that `x^(3) +y^(3)+z^(3)-3xyz=32`#cbsechallengingsum

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If x+y+z=8 then xy+yz+zx=20 then prove that `x^(3) +y^(3)+z^(3)-3xyz=32`
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Автор

Kiya samjhaya hai mam mtlb question ko halwa se bhi easy way me ban gaya thank u so much thanks a lot mam❤❤❤❤❤

sahmunni
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Nice explanation, very helpful for me

satyam
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Thank you so much mam...
No one explained this you did mam . TQ..🙂

maheshwaribootharaju
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Now I can solve these type of questions easily mam....

maheshwaribootharaju
Автор

If
x²+ y²+z²
= 725
xyz=3000
2 (xy+yz+zx) = 1300
Then find the value of x, y and z.​

tuhinbhattacharya