Solve Factorial Equations by Quartic Trick!

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Solve Factorial Equations by Quartic Trick!

Unlock the power of quartic equations to effortlessly solve factorial equations in this informative video. We'll reveal a clever quartic trick that simplifies complex factorials, making math seem like magic. Follow our step-by-step guide and master this technique, no matter your skill level. Say goodbye to the headache of factorial equations - it's easier than you think!

You will learn:
1. Factorial Equations
2. Olympiad Exam
3. Mathematics
4. Problem Solving
5. Value of X
6. Exam Preparation
7. Math Tutorial
8. Step-by-Step Guide
9. Math Olympiad
10. Algebraic identities
11. Math Olympiad Preparation
12. Factorial notation
13. Recursive formula

Time-Stamps:
0:00 Introduction
0:52 Domain
1:40 Recursive formula in factorials
3:44 Algebraic manipulations
4:55 Substitution
6:35 Quadratic equations
7:17 Solving quadratic equation by splitting middle term
9:13 Complex solutions
9:28 Real solutions
10:36 Verification

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Thanks for watching!
@infyGyan
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Thank you for explaining. [[ In this video, the way calculating needs an equation includes big numbers after getting (x+6)(x+5)(x+4)(x+3). ]]
As for the problem, the product of four consecutive natural numbers are 1680. The last digit is "0" and 5^4 < 1680 < 10^4 .
From these things, the candidate solution is 10×9×8×7 or 8×7×6×5 (because it should includes 5 or 10). 10×9×8×7=50400 (rejected) 8×7×6×5=1680
∴ (x+6)(x+5)(x+4)(x+3) = 8×7×6×5 ∴ x=2 I think this way's calculation is easier.

sy