Lorentz Trasformation Equations

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Finally an explanation that I could transfer into my own inertial frame of reference (my brain) and understand! Thank you!

zazac.
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Realy very nice..sir your voice is very clear and powerful to understand each word..this is very halpful for me, , ThanKs

sandeepmeena
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You never say "ERM"! You have my respect sir.

aquadockemi
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This may be the best video regarding the topic in entire youtube!
Thanks AKL!

vignesh
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you lectures are very clear and easier to understand, you motivates me to continues studying physics ..God bless you and your family... Paul from Kenya univeristy

muriithipaul
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Awesome  Video... Better than the professors ... 

ironman
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I am an Asian student..but still I am really used to to learn from ur lectures...they are soo soo clean and easy to understand... ur voice everything is perfect.. happy teachers day sir..

vrankyrule
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sir!
i want Michelson-Morley experiment explanation..

remielravela
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AMAZING! Thank you! You explain the material well!

juliaurbanowicz
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Thank you so very much for this series! You are very clear and concise. Keep up the great work!!!

zacharynewton
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I've been trying to understand more about the reality (including myself's) but found it was hard to get the time and length contraction intuitively, until I watched this clip! Many many thanks! 

tvkunkun
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Can we really treat a clock which uses pulse of light as stationary clock? The pulse of light is a part of the clock and this pulse is not at rest in any frame; rather it is moving at c. So how can we say that this is a stationary clock?

trsomas
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you are assuming contraction instead of proving it or demonstrating how alpha appears there; may be i dont understand.

sury
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from ct=α(x'+vt') and ct'=α(x-vt) divide t/t'=(x'+vt')/(x-vt) multiply and divide for α
t/t'=α(x'+vt')/α(x-vt) but α(x-vt)=x' then t=α(t'+vsqr(t')/x') but sqr(t')=sqr(x'/c)
finally t=α(t'+vx'/sqr(c)) formula of time Lorentz

alfredolanaro
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French is my mother tongue ... but you're explaining it so well that I could get most of it ! Well done man !

YanniMassi
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Why do we assume there is an alpha in the form of these equations at the outset: Why do we assume length contraction at the outset? Isn't length contraction a result of, rather than a reason for the Lorentz equations. So is this a bit circular?

Instead, why not assume a more general form i.e. x = Ax' + Bt' etc a priori (i.e. a form that assumes nothing except linearity) and go from there.
And similarly for time: t = Cx' +Dt' etc.
Then do step one, two and three (but you will need a fourth step where light travels along the y axis also to solve for A, B, C, D).

The way you're doing it seems to be a bit of a cheat, because we shouldn't know anything at the outset about length contraction from the two postulates. We only find out about that when we have the Lorentz equations surely.

Also, the explanation for
x = alpha(x'+vt') from the diagram. I don't quite get this.
Assuming the need for an alpha aside, I understand why it could be
x' = alpha(x-vt) but not the other way from the diagram.

And for the next diagram, I understand how that could be x = alpha(x'+vt') but not what is given here.

Are you sure these are correct.

markkennedy
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In the Length contraction equation, If there is a Frame of reference for both frames, then if frame F' prime is moving doesn't mean Its relative right. And Will there be a third frame of reference suppose to exist for both F and F prime?

kgvysakhkg
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wow thank you very much you have explain it so well. But I must agree after this I need a break.

christinamasilela
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work out one on spatial and temporal coordinate

davidnato
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Step 1 and 2 perfect, step 3 : at time t=t'=0, a photon of light leave the Origin O and O', and the Frame F' leave too with velocity V, according step 1.To avoid all complicate Math, let's take real numbers : X' = 1 m., distance between O and O'
Vt' = 2 m . So X = a [ X' + Vt' ] will be equal X= 3a. From X = C t ...t = X : C = 3a:C=3a/C..t = 3a/C...from X' = C t'...t' = X' : C = 1:C=1/C...t' =1/C...From Vt' = 2...V = 2 : t' =2 : 1/C = 2C.... V = 2C . Something is wrong...I use formulas from Video, just take any real number for distance .

gorgig