Equations with Complex Solutions (2 of 2: Solving & factorising)

[somayamahdi]

I don’t like math also not talk English but I like the way how you teach I wish when I become teacher teaching like you .

[geza]

OMG !!!! Eddie, I'm such a huge fan, I love your videos to learn my mathematics at home! You are a fingertip search away to learn at home and you are a great help to my success!

[ll]

I wish all the teachers are like you😘😘

[KingGisInDaHouse]

That last problem made me realize something neat. You can do this trick even if they’re not imaginaries. (x^2-6x+8)
X^2-6x+9-9+8
(X-3)^2-1
(x-3-1)(x-3+1)
(X-4)(x-2)

[suryakumarijuthuka]

May be you are the world's best teacher sirr😎😊

[JohnSmith-rftx]

8:39 -- For full satisfaction at this point, I would have loved you to have the students check that the answers were correct by multiplying out the two factors (z - i)*(z - (2+5i)) to show that they do indeed give you back the original quadratic in z.

[suryakumarijuthuka]

So for the 2nd u used completing the square method

[rodicabrudea]

how is sqrt (-3 + 4*i) = +/- (1 + 2*i). I don't get it :(. And how do you take a square root of " i "?

[aagamshah]

Hello sir, how did you calculate square root of that complex number?, please help

[troyyang]

Hi Eddie, so this really brings me a question whether we can square root a negative number. If we could, we are just simply assuming sqrt(-1)=i, whereas the definition of complex number is z=x+iy s.t i^2=-1

[Kamera_Photograpy]

2nd comment of the Staying home bc am sick :(

[tanishqkumar]

I wanna say a quote-
Alphabets in English: Dwayne Johnson.
Alphabets in Mathematics: The Rock.

[evanlewis]

Can Z^2 + 36 not be factored further, into z+6i and z-6i? It wasn’t done in the video, and I was wondering whether it would be wrong to do it, or whether Sir just didn’t do it

[JesusSavedSolomon]

I love the Lesson how your not wearing a mask